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aksik [14]
3 years ago
6

Deja is training for a race on Saturday. On Sunday, she runs 1/6 of a mile. On Monday she runs 1/5 of a mile. On Tuesday she run

s 1/4 of a mile. On Wednesday she runs 1/3 of a mile. On Thursday she runs 1/2 of a mile. Finally, on Friday, the day before the race, she runs a whole mile. If the length of the race is the same as the total distance Deja ran in preparation, how many miles is the race?
Mathematics
1 answer:
maksim [4K]3 years ago
8 0

Answer:

49/20 miles or 2.45 miles

Step-by-step explanation:

LCM(1,2,3,4,5,6,)=60

10/60+12/60+15/60+20/60+30/60+60/60=147/60=49/60 or 2.45

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Answer:

x = 5

y = 16

Step-by-step explanation:

Given

See attachment for parallelogram

Required

Find variables x and y

Solving for x, we have:

5x = 25 ---- Opposite sides of a parallelogram

\frac{5x}{5} = \frac{25}{5} ------ Divide both sides by 5

x = 5

Solving for y, we have:

3y - 1 = 47 ---- Opposite sides of a parallelogram

3y = 1 + 47 ------ Collect like terms

3y = 48

\frac{3y}{3} = \frac{48}{3} ---- Divide both sides by 3

y = 16

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3 years ago
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Kryger [21]
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6 0
3 years ago
Andy wants to buy 20 candy bars. If there is a special sale for buy 2 candy bars get one free. How much will it cost to buy 20 b
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7 0
3 years ago
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Kailee paid $14.84 for stamps. The number of .49-cents stamps was four less then three times the number of 21-cent stamps. How m
Akimi4 [234]

Answer:

Kailee bought 26 of 49-cents stamps and 10 of 21-cents stamps.

Step-by-step explanation:

Given:

Total Money paid for stamps = $14.84

Let the number of 49-cents stamps be x.

Also Let the number of 21-cents stamps be y.

Now Total Money paid is equal to sum of number of 49-cents stamps and number of 21-cents stamps.

100 cents = 1$

So 49 cents = $0.49

and 21 cents = $0.21

Hence equation be framed as;

0.49x+0.21y =14.84 \ \ \ \ equation \ 1

Also Given:

number of .49-cents stamps was four less then three times the number of 21-cent stamps.

hence we can say that;

x=3y-4\ \ \ \ equation \ 2

Now Substituting the value of equation 2 in equation 1 we get;

0.49(3y-4)+0.21y=14.84\\1.47y- 1.96+0.21y=14.84\\1.68y=14.84+1.96\\1.68y = 16.8\\y=\frac{16.8}{1.68}=10

Now substituting the value of y in equation 2 we get;

x=3y-4\\x=3\times10-4\\x=30-4\\x=26\\

Hence Kailee bought 26 of 49-cents stamps and 10 of 21-cents stamps.

7 0
3 years ago
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