Find the sum of 3+9+27...+6561

Mathematics

1 answer:

Nikolay [14]4 years ago

7 0

The sum of the first n terms of a geometric series with first term a₁ and common ratio r is given by the formula
$S_{n}=a_{1}\cdot\dfrac{r^{n}-1}{r-1}$

Then your sum is
$\sum\limits_{n=1}^{8}3^{n}=3\cdot\dfrac{3^{8}-1}{3-1}=9840$

The sum of this geometric series with first term 3 and common ratio 3 is ...
J 9840

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