Events
A = widget was produced by the old machine
B = widget was produced by the new machine.
D = widget was defective
Recall definition of conditional probability
P(X|Y)=P(X n Y)/P(Y) [ n represents set intersection operator ]
By the law of total probability,
P(A)=1/(1+3)=1/4
P(B)=3/(1+3)=3/4
Given:
Defective rate of new machine
P(D|B)=P(D n B)/P(B)=0.08 => P(D n B)=0.08*0.75=0.0600
Since P(B)=P(D n B)+P(~D n B)=0.75, this means that
P(~D n B)=0.75-0.0600 = 0.69
Proceed to calculate probability of non-defective widget given it is produced by the new machine:
P(~D|B) = P(~D n B)/P(B) = 0.69 / 0.75 = 0.92
Conclusion
The probability that the widget is not defective given that it was produced by the new machine is 0.92.
Answer:
3.5 or 3 2/4 a cup of white flower for each cup of rye flower
65 x 150%
or
65 x 1.5 = 97.5...
just remember to keep to the basics!
Answer: aₙ = -12 + (n - 1) 4
Step-by-step explanation:
aₙ = a + (n - 1) d
a = -12
d = 4
aₙ = -12 + (n - 1) 4
Function 1 :
y = 20x + 15......rate of change (slope) = 20, y int = 15
function 2 :
y = 10x + 25....rate of change (slope) = 10, y int = 25
function 1 has a greater rate of change then function 2
function 2 has a greater y int then function 1