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Roman55 [17]
4 years ago
8

Question 10 of 21

Mathematics
1 answer:
PSYCHO15rus [73]4 years ago
6 0

<u>ANSWER</u>

A. (4,12)

<u>EXPLANATION</u>

The equations are:

10x +2y = 64...(1)

and

3x - 4y = -36...(2)

To eliminate a variable we make the coefficients of that variable the same in both equations.

It is easier to eliminate x.

We multiply the first equation by 2 to get:

20x + 4y = 128...(3)

We add equations (2) and (3).

3x + 20x + 4y - 4y =  - 36 + 128

23x = 92

Divide both sides by 23

\frac{23x}{23}  =  \frac{92}{23}

x = 4

Put x=4 into equation (1).

10(4)+2y = 64

40+2y = 64

2y = 64 - 40

2y = 24

\frac{2y}{2}  =  \frac{24}{2}

y = 12

The solution is (4,12)

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