Question

Question 10 of 21

Answer 1

ANSWER

A. (4,12)

EXPLANATION

The equations are:

$10x +2y = 64...(1)$

and

$3x - 4y = -36...(2)$

To eliminate a variable we make the coefficients of that variable the same in both equations.

It is easier to eliminate x.

We multiply the first equation by 2 to get:

$20x + 4y = 128...(3)$

We add equations (2) and (3).

$3x + 20x + 4y - 4y = - 36 + 128$

$23x = 92$

Divide both sides by 23

$\frac{23x}{23} = \frac{92}{23}$

$x = 4$

Put x=4 into equation (1).

$10(4)+2y = 64$

$40+2y = 64$

$2y = 64 - 40$

$2y = 24$

$\frac{2y}{2} = \frac{24}{2}$

$y = 12$

The solution is (4,12)