Answer:
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
Step-by-step explanation:
Given
![$\[x^2 + 22x + \underline{~~~~}.\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20%5Cunderline%7B~~~~%7D.%5C%5D%24)
Required
Fill in the gap
Represent the blank with k
![$\[x^2 + 22x + k\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20k%5C%5D%24)
Solving for k...
To do this, we start by getting the coefficient of x
Coefficient of x = 22
<em />
Divide the coefficient by 2
Take the square of this result, to give k
Substitute 121 for k
The expression can be factorized as follows;
<em>Hence, the quadratic expression is </em><em></em>
1:B, 2:A, 3:D, 4:A
those are the answers
Part A:
f(x)=30(1.2)^x
f(x)=45+3x
Part B: Neighborhood A is 74.6496, so that rounds to 75 homes, and Neighborhood C is exactly 60 homes
Part C:
i would graph them in a graphing calculator, and use the functions to see where the 2 lines intersect.
The x value for when they intersect (# of years) is 3.3207883, so approx. 3.3 years for them to be equal
That's pretty expensive its usually cheaper. I would look for another gym. This isn't really a question though.
