PLS HELP ME WITH ALL 4! (SHOW WORK!!) + LOTS OF POINTS!!

A can of enchilada sauce contain 3 1 /2 servings. If one serving contains 250 mg of sodium, how many grams of sodium are in the

xeze [42]

Answer:

0.875 grams

Step-by-step explanation:

Make a proportion

There are 250 mg in 1 serving, and x mg in 3.5 servings

250/1=x/3.5

Cross multiply

1*x=3.5*250

x=875 mg

Convert mg to g

1 mg is equal to 0.001 g

To find the amount of grams, divide the amount of mg by 1000

875/1000=0.875

So, there are 0.875 grams in the entire can

Hope this helps! :)

3 0

2 years ago

What is 82 divided by 4 in whole numbers

mr_godi [17]

It would 20.5, but rounded off would be 21

8 0

2 years ago

HELP PLS ITS BEEEN AN HOUR im going to cry ):

miss Akunina [59]

Answer: Don't cry please you'll be okay.

Step-by-step explanation:

3 0

2 years ago

A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran

mart [117]

Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

$X=48$ number of vehicles classified as sports utility.

$n=500$ random sample taken

$\hat p=\frac{48}{500}=0.096$ estimated proportion of vehicles classified as sports utility vehicles.

$p$ true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.5=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070$

$0.096 + 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.121$

And the 95% confidence interval would be given (0.070;0.121).

We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

7 0

2 years ago

Two cells are viewed and measured under a microscope. The approximate diameter

nikklg [1K]

Answer:

option D. 4.7 x 10-4 m

Step-by-step explanation:

<u><em>The correct question is</em></u>

• cell P: 5.0 x 10-4 meters

• cell Q: 3.0 x 10-5 meters

we have

The diameter of cell P is $5*10^{-4}\ m$