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3 years ago

What is the compound's systematic name?

Chemistry

1 answer:

GalinKa [24]3 years ago

8 0

Answer: methane

Explanation:

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Which is NOT true of ionic bonding?

WARRIOR [948]

Answer:

D is wrong

Explanation:

it doesn't involves any kind of sharing of electrons

6 0

3 years ago

What volume of lead (of density 11.3 g/cm3) has the same mass as 330 cm3 of a piece of redwood (of density 0.38 g/cm3)?

zimovet [89]

Answer:

The sample of lead has a volume of 11.1 cm³

Explanation:

Step 1: Data given

x cm³ lead has a density of 11.3 g/cm³

it has the same mass as 330cm³ of a piece of redwood with density 0.38g/cm³

Step 2: Calculate mass of the piece of redwood

Density = mass/volume

mass = density * volume

Mass of the piece of redwood = 0.38 g/cm³ * 330cm³ = 125.4 grams

Since the sample of lead has the same mass, it also has a mass of 125.4 grams

Step 3: Calculate volume of the lead

Density = mass/ volume

Volume = mass/ density

Volume of lead = 125.4g / 11.3g/cm³ = 11.097 cm³≈11.1 cm³

The sample of lead has a volume of 11.1 cm³

3 0

3 years ago

The ice blocks demonstrated A. conduction B. convection C. radiation

choli [55]

B, the ice blocks demonstrated convection :)

7 0

2 years ago

Read 2 more answers

Anyone know this????

Anastasy [175]

The correct answer is the first one

3 0

3 years ago

Choose the compound below that should have the highest melting point according to the ionic bonding model. Choose the compound b

Bingel [31]

Answer:

AlN has highest melting point among given.

Explanation:

As per ionic model, ionic compounds are held together by electrostatic force. The ionic compound having strong electrostatic force will have high melting point.

Electrostatic force is proportional to charge and size of constituent ions.

$F=k \frac{q_+\times q_-}{r^2}$

In case of MgO

Charge on Mg = +2

Charge on O = -2

$F=-k \frac{(+2)\times (--2)}{r^2}=\frac{4k}{r^2}$

In case of LiF

Charge on Li = +1

Charge on F = -1

$F=-k \frac{(+1)\times (-1)}{r^2}=\frac{1k}{r^2}$

In case of AlN

Charge on Al = +3

Charge on N = -3

$F=-k \frac{(+3)\times (-3)}{r^2}=\frac{9k}{r^2}$

In case of RbF

Charge on Rb = +1

Charge on F = -1

$F=-k \frac{(+1)\times (-1)}{r^2}=\frac{1k}{r^2}$

In case of CaS

Charge on Ca = +2

Charge on S = -2

$F=-k \frac{(+2)\times (-2)}{r^2}=\frac{4k}{r^2}$

As magnitude of electrostatic force is highest in AlN, therefor, it has highest melting point.

4 0

3 years ago