1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mazyrski [523]
3 years ago
14

Calculate the temperature at which air possess the density equal to that of hydrogen at 0%. Density of air at NTP is 14.4.​

Chemistry
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

Density of air at nTP is 14.4. Ans: 3658.2 °C. GOOD LESSONS ♡

You might be interested in
Temperature is a(n)<br> ecosystem.<br> component of an ecosystem.
guajiro [1.7K]

Answer:

Temperature is an abiotic component of an ecosystem

Explanation:

6 0
3 years ago
Baking soda has a pH of 8. Its a(n) _________ substance
Stolb23 [73]

Answer:

it's an acid

Explanation:

because itis soda

4 0
3 years ago
What is the volume mL of 2 degree celsius?
Anestetic [448]

Answer:

Question not very specific, but here is an answer you might be looking for. Density of object at 2 degrees C, 0.99997 g/mL. Hope it IS the answer you are looking for!

Explanation:

7 0
3 years ago
Helpppp pleaseee ill give brainliest
Studentka2010 [4]

Answer:

The answers are in the explanation.

Explanation:

The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:

Increasing temperature of ice from -10°C - 0°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g

Q = 2.06J/g°C*10°C*10g

Q = 206J

Change from solid to liquid:

The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:

Q = 333.55J/g*10g

Q = 3335.5J

Increasing temperature of liquid water from 0°C - 100°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g

Q = 4.18J/g°C*100°C*10g

Q = 4180J

Change from liquid to gas:

The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:

Q = 2260J/g*10g

Q = 22600J

Increasing temperature of gas water from 100°C - 120°C:

Q = S*ΔT*m

Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g

Q = 1.87J/g°C*20°C*10g

Q = 374J

Total Energy:

206J + 3335.5 J + 4180J + 22600J + 374J =

30695.5J =

30.7kJ

5 0
3 years ago
What property of gases confirms that the space between the particles of gas is significantly larger than when the same substance
leva [86]
The answer is D. Compressibility
5 0
3 years ago
Other questions:
  • A student based the analysis of Cu(II) in a sample on the formation of the blue complex [Cu(H2O)6]+2. A standard solution was ma
    6·1 answer
  • turning on a tv is an example of _______ energy being transformed into_________ energy and________energy
    8·1 answer
  • Au(NO3)3 added with water? Aq or s?
    12·1 answer
  • What is a dynamic process?
    15·1 answer
  • Fluorine is a toxic, reactive gas. Witch representation (structural formula, electron dot structure, or three-dimensional model)
    8·1 answer
  • Which of the following statements explains why atoms are always neutral in charge
    14·1 answer
  • Chromatography
    6·1 answer
  • Sodium sulphate reacts with calcium nitrate to produce sodium nitrate and calcium sulphate. A) identify the reactants and produc
    9·1 answer
  • What is the Kc and Kp of <br>P4(s)+6Cl2(g) = 4PCla-​
    8·1 answer
  • an oven adds 2260 j heat to a zinc tray that weighs 195g of the tray starts at 25 what is the final temperature of the tray
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!