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4 years ago

What is pH???

Chemistry

2 answers:

vazorg [7]4 years ago

6 0

I think it is the second answer

LUCKY_DIMON [66]4 years ago

3 0

4) the concentration of hydrogen ions in a solution

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A BaSO4 slurry is ingested before the gastrointestinal tract is x-rayed because it is opaque to x-rays and defines the contours

NNADVOKAT [17]

Explanation:

The given reaction equation is as follows.

$BaSO_{4}(s) \rightleftharpoons Ba^{2+}(aq) + SO_{4}^{2-}(aq)$

The value of $\Delta G^{o}$ = 59.1 kJ/mol

We know that ,

$\Delta G^{o} = -RT ln K_{sp}$

or, $ln K_{sp} = -(\frac{\Delta G^{o}}{RT})
$

= -(\frac{59.1 kJ/mol}{(8.314 \times 10^{-3} kJ/mol.K \times 310 K))}[/tex]

= -22.93

or, $K_{sp} = e^{-22.93}$

= $1.1 \times 10^{-10}$

$K_{sp} = [Ba^{2+}][ SO_{4}^{2-}]$

Therefore, $[Ba^{2+}] =\sqrt{K_{sp}}$

= $\sqrt{ 1.1 \times 10^{-10}}$

= $1.05 \times 10^{-5} M$

Therefore, we can conclude that the value of $[Ba^{2+}]$ in the intestinal tract is $1.05 \times 10^{-5} M$ .

7 0

3 years ago

Which metal is most likely to be formed easily into

Nataly [62]

Answer:

answer is gold

Explanation:

bcz gold is having a property of malleable so it can be drawn into thin sheets

5 0

4 years ago

Read 2 more answers

Which element is humus especially rich in? oxygen carbon nitrogen or tungsten

amid [387]

Answer:

Carbon

Explanation:

looked it up

5 0

3 years ago

What are three methods of measuring the volume of an object?

Anarel [89]

L×w×h=v
length times width times height equals volume
the order in which you multiply does not matter

5 0

3 years ago

What is the molality of a solution prepared by dissolving 75.8 g of ethylene glycol, HOCH2CH2OH, in 1.55 L of water? Assume the

GaryK [48]

Answer:

0.787 mol.Kg⁻¹ or 0.787 m

Explanation:

Data Given:

Mass = m = 75.8 g

Volume = V = 1.55 L = 1550 mL

M.Mass of Ethylene Glycol = 62.07 g/mol

Density of water = d = 1.0 g/mL

To Find:

Molality = ??

Molality is a unit of concentration and is defined as the number of moles of solute per Kg of a solvent.

Molality = Moles of Solute / Kg of Solvent --- (1)

First Calculate Moles of Solute as;

Moles = Mass / M.Mass

Moles = 75.8 g / 62.07 g/mol

Moles = 1.22 moles

Secondly calculate mass of water as,

mass of water = density × volume

mass of water = 1.0 g/mL × 1550 mL

mass of water = 1550 g or 1.55 Kg

Now, putting values of moles and mass of solvent in equation 1,

Molality = 1.22 mol / 1.55 Kg

Molality = 0.787 mol.Kg⁻¹ or 0.787 m

7 0

3 years ago