Answer:
The probability that at least 280 of these students are smokers is 0.9664.
Step-by-step explanation:
Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers
The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.
But the sample selected is too large and the probability of success is close to 0.50.
So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
1. np ≥ 10
2. n(1 - p) ≥ 10
Check the conditions as follows:

Thus, a Normal approximation to binomial can be applied.
So,

Compute the probability that at least 280 of these students are smokers as follows:
Apply continuity correction:
P (X ≥ 280) = P (X > 280 + 0.50)
= P (X > 280.50)

*Use a <em>z</em>-table for the probability.
Thus, the probability that at least 280 of these students are smokers is 0.9664.
The answer is b. The 2 will make it stretched vertically.
1.50 is charging but if p= 20 + 3 and that 23 then p is 23 divided by 1.50 and that going to be your answer
Answer:
I dont know but If that was my sister she would be dead
Step-by-step explanation:
The answer would be positive if all 3 signs were the same. Yes, the product of two integers with the same sign will be positive, but that goes for any number of integers as long as they still have the same sign.