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3 years ago

Someone help plzz 5 3/16 x 300 =

Mathematics

1 answer:

Kitty [74]3 years ago

4 0

Answer:

The answer is 1556.25

Step-by-step explanation:

5 3/16 = 5.1875

5.1875 x 300 = 1556.25

Hope this helps!

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What is 45/90= to <br> i need help

Sati [7]

Answer:

1/2

Step-by-step explanation:

45/90 ÷ 45/45 = 1/2

5 0

3 years ago

Read 2 more answers

Erin feeds her dog 7/10 cup of food a day . With 3/10 cup canned and the rest dry . She also gives her dog 1 treat a day . How m

gavmur [86]

Answer:

$2\frac{4}{5}\ \ or \ 2.8 \ \ cups$

Step-by-step explanation:

-The total portion fed to the dog is 7/10 cup

Canned-3/10
Dry=7/10-3/10=4/10

-One week has 7 days. we multiply the dry portion per day by the number of days in a week.

$Dry= Total -Canned\\\\=\frac{7}{10}-\frac{3}{10}\\\\=0.40 \ cup\\\\Dry \ per \ Week= Dry/ day\times days\\\\=0.40\times 7\\\\=2\frac{4}{5}\ or\ 2.8 \ cups$

Hence, Erin feed her dog 2 4/5 0r 2.8 cups of dry food

5 0

3 years ago

4/x-1+6/x+1=-12/x^2-1

Mademuasel [1]

$\frac{4}{x - 1} + \frac{6}{x + 1} = \frac{-12}{x^{2} - 1}$

$\frac{4(x + 1)}{(x - 1)(x + 1)} + \frac{6(x - 1)}{(x - 1)(x + 1)} = \frac{-12}{x^{2} - 1}$

$\frac{4x + 4}{x^{2} - 1} + \frac{6x - 6}{x^{2} - 1} = \frac{-12}{x^{2} - 1}$

$\frac{10x - 2}{x^{2} - 1} = \frac{-12}{x^{2} - 1}$

$(10x - 2)(x^{2} - 1) = -12(x^{2} - 1)$
$10x^{3} - 10x^{2} - 2x^{2} + 2 = -12(x^{2}) + 12(1)$
$10x^{3} - 12x^{2} + 2 = -12x^{2} + 12$
$10x^{3} - 12x^{2} + 12x^{2} + 2 = -12x^{2} + 12x^{2} + 12$
$10x^{3} + 2 - 2 = 12 - 2$
$\frac{10x^{3}}{10} = \frac{10}{10}$

$x^{3} = 1$
$x = 1$

4 0

3 years ago

Multiply or divide as indicated (a+b)^9 / (a+b)^4

Allushta [10]

I believe (a+b)^5 would be the answer

5 0

3 years ago

number 4 I have absolutely no idea how to do. I generally understand finding distance on the coordinate plane but this has reall

Over [174]

For Part A, in creating the square, you did it correctly.

Now for Part B, you can create a right triangle by adding a point at -4, -3, and we'll call it, say, T.

Then you can use the Pythagorean's Theorem to find the length of one side of the square.

The Pythagorean's Theorem is $a^{2} + b^{2} = c^{2}$

A would be the distance between P and T, and B would be the distance between Q and T. So then, a would be 7, and B would be 2.

To fill it in, it would be $7^{2} + 2^{2} = c^{2}$

or 49 + 4 = $c^{2}$

or 53 = $c^{2}$

or $\sqrt{53}$ = x

Which is equal to about 7.28

Now multiply that by 4 to get the perimeter, or 29.12

So the perimeter would be about 29.12

3 0

3 years ago