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jek_recluse [69]
3 years ago
11

A polynomial has been factored below, but some constants are missing. 2x^3 –6x^2 –8x=ax(x+b)(x+c) What are the missing values of

a, b, and c?
Mathematics
2 answers:
Anarel [89]3 years ago
7 0
2x (x - 4) (x + 1). A=2, B=-4, C=1
sdas [7]3 years ago
4 0

Answer:

Step-by-step explanation:

hello :

2x^3 –6x² –8x=ax(x+b)(x+c)

2x^3 –6x² –8x= 2x(x²-3x-4)

but : x²-3x-4 = (x+1)(x-4)

so : 2x^3 –6x² –8x= 2x(x+1)(x-4)

a=2    and     b=1   and     c= -4

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