A polynomial has been factored below, but some constants are missing. 2x^3 –6x^2 –8x=ax(x+b)(x+c) What are the missing values of

Question

3 years ago

11

a, b, and c?

2 answers:

Anarel [89] · Answer 1 · 2022-05-10T13:56:37+03:00

7 0

2x (x - 4) (x + 1). A=2, B=-4, C=1

sdas [7] · Answer 2 · 2022-05-10T15:28:31+03:00

sdas [7]3 years ago

4 0

Answer:

Step-by-step explanation:

hello :

2x^3 –6x² –8x=ax(x+b)(x+c)

2x^3 –6x² –8x= 2x(x²-3x-4)

but : x²-3x-4 = (x+1)(x-4)

so : 2x^3 –6x² –8x= 2x(x+1)(x-4)

a=2 and b=1 and c= -4