Question

A polynomial has been factored below, but some constants are missing. 2x^3 –6x^2 –8x=ax(x+b)(x+c) What are the missing values of a, b, and c?

Answer 1

2x (x - 4) (x + 1). A=2, B=-4, C=1

Answer 2

Answer:

Step-by-step explanation:

hello :

2x^3 –6x² –8x=ax(x+b)(x+c)

2x^3 –6x² –8x= 2x(x²-3x-4)

but : x²-3x-4 = (x+1)(x-4)

so : 2x^3 –6x² –8x= 2x(x+1)(x-4)

a=2    and     b=1   and     c= -4