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2 years ago

4. Which point on the number line represents 0.3?

Mathematics

2 answers:

seropon [69]2 years ago

8 0

Answer: it’s C because it’s the one that’s closer to 3 if u need help just ask

Step-by-step explanation:

Hope this helps

-3

Dafna11 [192]2 years ago

5 0

Answer:

Point C

Step-by-step explanation:

because the number is 0.3 you need to start at zero on the number line and go forward 3 marks. That will lead you to your answer of 0.3

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What is 1/2 x 2/3 x 3/4

inna [77]

I believe the answer is 0.25

4 0

3 years ago

Read 2 more answers

Brian bought a new air conditioning unit on his credit card. The unit had a base price of $435. Brian made no other purchases on

Svetlanka [38]

Answer:

D is the correct answer

Step-by-step explanation:

Given:

Unit base price: $435

Credit Card interest rate, i = 9.4% compounded monthly; i = 0.00783/month comp monthly

n = 1.5 years = 18 months

sales tax = 8.51%

First, determine the actual price of the unit by adding the sales tax to the base price of the unit:

$435 * (1 + 0.0851)

Actual price = $472.0185

So, the total amount paid by Brian should be higher than the actual price since he used his credit card. Use the formula from economics:

F = P (1+i)^n

F = $507.96

Therefore, the total amount paid by Brian is $507.96.

(Hope this helps can I pls have brainlist (crown) ☺️)

3 0

2 years ago

If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in

Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, of the box with a square base are described below:

$A_{s} = l^{2}+h\cdot l$ (1)

$V = l^{2}\cdot h$ (2)

Where:

$l$ - Side length of the base, in centimeters.

$h$ - Height of the box, in centimeters.

By (2), we clear $h$ within the formula:

$h = \frac{V}{l^{2}}$

And we apply in (1) and simplify the resulting expression:

$A_{s} = l^{2}+ \frac{V}{l}$

$A_{s}\cdot l = l^{3}+V$

$V = A_{s}\cdot l -l^{3}$ (3)

Then, we find the first and second derivatives of this expression:

$V' = A_{s}-3\cdot l^{2}$ (4)

$V'' = -6\cdot l$ (5)

If $V' = 0$ and $A_{s} = 30000\,cm^{2}$ , then we find the critical value of the side length of the base is:

$30000-3\cdot l^{2} = 0$

$3\cdot l^{2} = 30000$

$l = 100\,cm$

Then, we evaluate this result in the expression of the second derivative:

$V'' = -600$

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

$V = 30000\cdot l - l^{3}$

$V = 2000000\,cm^{3}$

The largest possible volume of the box is 2000000 cubic meters.

4 0

2 years ago

Roberto rowed 20 miles downstream in 2.5 hours. The trip back, however, took him 5 hours. Find the rate that Roberto rows in sti

almond37 [142]

Answer:

<em>Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour</em>

Step-by-step explanation:

<u>Relative Speed</u>

When a body is moving at a constant speed v, the distance traveled in a time t is:

$d=v.t$

When Roberto rows downstream, his speed in still water is added to the speed of the water, making it easier to travel the required distance.

When Roberto rows upstream, his speed in still water is affected by the speed of the water, both are subtracted and the required distance is covered in more time.

Let's call

x = Roberto's rowing speed in still water

y = Speed of the river current

The speed when rowing downstream is x+y, thus the distance traveled is

$d=(x+y).t_1$

Where t1=2.5 hours. Substituting values:

$20=(x+y)*2.5$

Rearranging, we find the downstream equation:

$2.5x+2.5y=20\qquad[1]$

The speed when rowing upstream is x-y, and the distance traveled is

$d=(x-y).t_2$

Where t2=5 hours. Substituting values:

$20=(x-y)*5$

Rearranging, we find the upstream equation:

$5x-5y=20\qquad[2]$

Multiplying [1] by 2:

$5x+5y=40$

Adding this equation to [2]:

$10x=60$

Solving:

$x=60/10=6$

Dividing [2] by 5:

$x-y=4$

Solving for y

$y=x-4=6-4=2$

Thus, Roberto's speed in still water is 6 miles/hour and the river speed is 2 miles/hour

3 0

3 years ago

NO LINKS!! Please help me with this problem

Anastaziya [24]

Answer:

y²/324 -x²/36 = 1

Step-by-step explanation:

Where (0, ±b) are the ends of the transverse axis and y = ±(b/a)x describes the asymptotes, the equation of the hyperbola can be written as ...

y²/b² -x²/a² = 1

<h3>Application</h3>

Here, we have transverse axis endpoints of (0, ±18) and asymptotes of y = ±3x, so we can conclude ...

b = 18

b/a = 3 ⇒ a = 18/3 = 6

The equation of the hyperbola in standard form is ...

y²/324 -x²/36 = 1

7 0

2 years ago