If CE bisects ZBCD and if m ZBCE = 3x - 6
1 answer:
Answer:
m∠BCD = 90°
∠BCD is a right angle
Step-by-step explanation:
<em>If a ray bisects an angle, that means it divides the angle into two equal parts in measure</em>
∵ Ray CE bisects ∠BCD
→ Means divide it into two angles BCE and ECD which equal in measures
∴ m∠BCE = m∠ECD = m∠BCD
∵ m∠BCE = 3x - 6
∵ m∠ECD = 2x + 11
→ Equate them to find x
∴ 3x - 6 = 2x + 11
→ Add 6 to both sides
∵ 3x - 6 + 6 = 2x + 11 + 6
∴ 3x = 2x + 17
→ Subtract 2x from both sides
∵ 3x - 2x = 2x - 2x + 17
∴ x = 17
∵ m∠BCE = m∠BCD
→ Substitute x in the measure of ∠BCE to find it, then use it to
find m∠BCD
∵ m∠BCE = 3(17) - 6 = 51 - 6
∴ m∠BCE = 45°
∵ 45 = m∠BCD
→ Multiply both sides by 2
∴ 90 = m∠BCD
∴ m∠BCD = 90°
→ The measure of the acute angle is less than 90°, the measure of
the obtuse angle is greater than 90°, and the measure of the
right angle is 90°
∴ ∠BCD is a right angle
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Answer:
Option B is correct =
Step-by-step explanation:
<u>The complete question is:</u> Which of the following options have the same value as 30% of 81?
Group of choices is:
(A)
(B)
(C)
(D)
(E)
Now, the expression given to us is 30% of 81.
Simplifying the above expression we get;
30% of 81 =
= =
Now, we will solve each of the given options and then see which option matches with our calculation.
Option (A) is given;
=
This doesn't match with our answer, so this option is not correct.
Option (B) is given;
<u><em>This matches with our answer, so this option is correct.</em></u>
Option (C) is given;
This doesn't match with our answer, so this option is not correct.
Option (D) is given;
=
This doesn't match with our answer, so this option is not correct.
Option (E) is given;
This doesn't match with our answer, so this option is not correct.
Answer:
g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))
Step-by-step explanation:
Using the fundamental theorem of calculus
Taking the derivative of the integral gives back the function
Since the lower limit is a constant when we take the derivative it is zero
d/dx
g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))
Replacing t with x
g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))