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amid [387]
3 years ago
11

A solution of ammonium carbonate is mixed with a solution of magnesium nitrate. If magnesium carbonate is insoluble in water, wh

at is the reaction?​

Chemistry
1 answer:
Doss [256]3 years ago
3 0

Double displacement/ Double decomposition/ Metathesis

Explanation:

The insoluble magnesium carbonate produced is called a precipitate. In a double displacement reaction, ionic compounds combines to produce precipitates.

In this type of reaction, species are usually exchange to form new compounds.

One of the following is a driving force for double displacement reaction:

  • Formation of insoluble compounds called precipitates.
  • Formation of water or any other non - ionizing compound
  • liberation of a gaseous product.

learn more:

Precipitate brainly.com/question/8896163

#learnwithBrainly

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pav-90 [236]
Answer ————
60.8 g ammonia
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2 years ago
One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO
zhenek [66]
Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
 2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂<span>O(g)

The stoichiometric ratio between </span>Na₃(CO₃)(HCO₃)·2H₂O(s)  and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
                                                                                     = 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
                                                         = 1000 x 10³ g / 226 g mol⁻¹
                                                         = 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x \frac{3}{2}
                                                     = 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
                                        = 703540.02 g
                                        = 703.540 kg

Hence, the theoretical yield of Na₂CO₃ =  703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
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7 0
3 years ago
Select the correct answer. What is the percent composition of silicon in silicon carbide (SiC)? A. 28% B. 50% C. 70% D. 142%
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Answer:

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3 years ago
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Free_Kalibri [48]

Answer:

Solution A is a Weak Alkali, Solution B is a strong Acid.

Explanation:

At pH 10, the colour is blue, therefore it's a weak alkali.

At pH 1, the colour is red, therefore it's a strong Acid.

7 0
3 years ago
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