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Westkost [7]
3 years ago
6

Practice Problems (show all work):

Chemistry
1 answer:
tekilochka [14]3 years ago
6 0
1a 1
b 4
c 5
2 (5.44x10^2)(2.5x10^-3)(7.9x10^-3) = 1.1x10^-6
3 750/1000 = 0.750
4 50/0.5 = 100 mL
5 He came up with the modern ideals for chemsitty
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Helium gas diffuses 4 times as fast as an unknown gas. What is relative molecular mass of the gas​
Inessa05 [86]

The relative molecular mass of the gas​ : 64 g/mol

<h3>Further explanation</h3>

Given

Helium rate = 4x an unknown gas

Required

The relative molecular mass of the gas​

Solution

Graham's Law

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

r₁=4 x r₂

r₁ = Helium rate

r₂ = unknown gas rate

M₁= relative molecular mass of Helium = 4 g/mol

M₂ = relative molecular mass of the gas​

Input the value :

\tt \dfrac{4r_2}{r_2}=\sqrt{\dfrac{M_2}{4} }\\\\16=\dfrac{M_2}{4}\\\\M_2=64~g/mol

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Which of the following is an example of a liquid and gas mixture? *
Stolb23 [73]

Answer:

Carbonated Water

Explanation:

Carbonated water is a mixture of carbon dioxide gas and water.

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Imagine that you are observing an enzyme-catalyzed reaction in lab. every time you add more enzyme, the reaction rate increases
tester [92]

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