15396 g
tell me if its correct
Answer:
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Answer:
The partial pressure of BrCl at equilibrium is 0.08 atm.
Explanation:
The equilibrium constant of the reaction is given by =

initial
0 0 0.500 atm
At equilbrium
p p (0.500-2p)
The equilibrium constant's expression of the reaction is given by ;
![K_p=\frac{[BrCl]^2}{[Br_2][Cl_2]}](https://tex.z-dn.net/?f=K_p%3D%5Cfrac%7B%5BBrCl%5D%5E2%7D%7B%5BBr_2%5D%5BCl_2%5D%7D)

Solving for p:
p = 0.21 atm
The partial pressure of BrCl at equilibrium is:
(0.500-2p) = (0.500 - 2 × 0.21 )atm = 0.08 atm[/tex]
Answer:
Explanation:
(KF)2(Al2O3)3(SiO2)6(H2O)
molecular formula
K₂F₂Al₆Si₆O₂₂H₂
2 x 39 + 2 x 19 + 6 x 27 + 6 x 28 + 22 x 16 + 2 x 2
= 78 + 38 + 162+ 168+ 352+ 4
= 802
Percentage of K = 78 x 100 / 802
= 9.72 %
Percentage of F = 38 x 100 / 802
= 4.74 %
Percentage of Al = 162 x 100 / 802
= 20.2 %
Percentage of Si = 168 x 100 / 802
= 20.9 %
Percentage of O = 352 x 100 / 802
= 43.9 %
Percentage of H = 4 x 100 / 802
= .54 %