The question seem to be incomplete but I found the complete question which is:
If you are performing this test on an unknown organism, why is it a good idea to run simultaneous tests on known phenylalanine-positive and phenylalanine-negative organisms?
Here is the Answer:
Inoculation of a positive control and success from it includes certainty to negative outcomes on an unknown organism. That is, you know the test is working effectively, so the negative outcome is most likely precise. Without the positive control, there is dependably a component of uncertainty whether the negative outcome is a genuine negative or a false negative. performing the test on a known phenlalanine-negative organism is valuable in that it exhibits what a negative outcome looks like.
B- Metamorphic rocks. metamorphic rocks are formed through the change of igneous and sedimentary rocks. which sandstone and basalt are. metamorphic rocks are also formed through heat and pressure
Answer:
A
Explanation:
Employee A gets a bigger pay rise by 5%
Answer:
Suppose that at a given point along a capillary, the following forces exist: Capillary hydrostatic pressure (HPc) = 30 mmHg Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg Capillary colloid osmotic pressure (OPc) = 25 mmHg Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg. The net filtration pressure at this point in the capillary is <u>7mmHg.</u>
Explanation:
Capillary hydrostatic pressure (HPc) = 30 mmHg
Interstitial fluid hydrostatic pressure (HPif) = 0 mmHg
Capillary colloid osmotic pressure (OPc) = 25 mmHg
Interstitial fluid colloid osmotic pressure (OPif) = 2 mmHg
Net filtration pressure= hydrostatic pressure gradient - Oncotic pressure gradient
Hydrostatic pressure gradient = Capillary hydrostatic pressure - Interstitial hydrostatic pressure = 30mmHg - 0 mmHg = 30 mmHg
Oncotic pressure gradient = Capillary colloid osmotic pressure - Interstitial fluid colloid osmotic pressure =25 - 2 = 23 mmHg
Net filtration pressure= hydrostatic pressure gradient - Oncotic pressure gradient = 30 mmHg - 23 mmHg = 7 mmHg.
Hence, The net filtration pressure at this point in the capillary is <u>7mmHg.</u>
