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2 years ago

Josh currently bench presses 150 lbs. He increases that amount by 10% a month for 3 months. About how much can bench press now?

Mathematics

2 answers:

Mice21 [21]2 years ago

7 0

10% of 150 is 15.

15*3 (months) + 45

150 + 45 = 195lbs

gregori [183]2 years ago

5 0

150 x 1.1
((1.1 is 110% of 150 so 10% more))
165 x 1.1
181.5 x 1.1
199.65 x 1.1 =
219.615
((You might need to simplify))

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It will take total 90 minutes to finish the book and 60 minutes to read the left 40 pages.

<h3>What is Ratio and Proportion ?</h3>

When two numbers can be written as p/q is called a Ratio , and when two ratios are equal they are said to be in proportion .

It is given that

Jeremy is reading a 60-page book.

The time taken to read 20 pages is 30 minutes

Then it can be written as 20:30 = 2:3

The rate of reading is same so To read the rest 40 pages is given by

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40: x = 2:3

40*3/2 = x

x = 60 minutes

Therefore it will take total 90 minutes to finish the book and 60 minutes to read the left 40 pages.

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3 years ago

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2 years ago

If we wanted to create a new 90% confidence interval from a different sample for the proportion of those with a two on one date

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Answer: 271

Step-by-step explanation:

The formula we use to find the sample size is given by :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

, where $z_{\alpha/2}$ is the two-tailed z-value for significance level of $(\alpha)$

p = prior estimation of the proportion

E = Margin of error.

If prior estimation of the proportion is unknown, then we take p= 0.5 , the formula becomes

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2$

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2$

Given : Margin of error : E= 0.05

Confidence level = 90%

Significance level $\alpha=1-0.90=0.10$

Using z-value table , Two-tailed z-value for significance level of $0.10$

$z_{\alpha/2}=1.645$

Then, the required sample size would be :

$n=0.25(\dfrac{1.645}{0.05})^2$

Simplify,

$n=270.6025\approx271$

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3 years ago

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