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WARRIOR [948]
3 years ago
6

What are the solutions to the quadratic equation x^2-16=0

Mathematics
2 answers:
frutty [35]3 years ago
8 0
Simplifying this, we get:
(x+4)(x-4) = 0
Now, to get 0, we can replace x for one of these things to make 0, so:
x can either be 4, or -4
serg [7]3 years ago
4 0

Answer:

Solution of the quadratic equation x^{2}-16=0 is 4 and -4.

Step-by-step explanation:

The given quadratic equation is x^{2}-16=0

To find the solutions of the quadratic equation, we first need to make the factors of x^{2}-16.

We know that we can write a^{2} -b^{2} =(a-b)(a+b)

So, x^{2} -16 can be written as x^{2} -4^{2}, and it can be further written as (x-4)(x+4).

Now, on solving  x^{2}-16=0 we have,

x^{2}-16=0

x^{2} -4^{2}=0

(x-4)(x+4)=0

So, either x-4=0 or x+4=0

                 x=4   or x=-4

Hence, the solution of the quadratic equation x^{2}-16=0 is 4 and -4.

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