Question

What are the solutions to the quadratic equation x^2-16=0

Answer 1

Simplifying this, we get:
(x+4)(x-4) = 0
Now, to get 0, we can replace x for one of these things to make 0, so:
x can either be 4, or -4

Answer 2

Answer:

Solution of the quadratic equation $x^{2}-16=0$ is 4 and -4.

Step-by-step explanation:

The given quadratic equation is $x^{2}-16=0$

To find the solutions of the quadratic equation, we first need to make the factors of $x^{2}-16$.

We know that we can write $a^{2} -b^{2} =(a-b)(a+b)$

So, $x^{2} -16$ can be written as $x^{2} -4^{2}$, and it can be further written as $(x-4)(x+4)$.

Now, on solving  $x^{2}-16=0$ we have,

$x^{2}-16=0$

$x^{2} -4^{2}=0$

$(x-4)(x+4)=0$

So, either $x-4=0$ or $x+4=0$

                 $x=4$   or $x=-4$

Hence, the solution of the quadratic equation $x^{2}-16=0$ is 4 and -4.