The answer is 800 meters.
You find this by taking the total distance of the first lap and doubling it. You could also find it by adding 400 meters to 400 meters, which would total at 800 meters
Correct answer is (D. Once created in bone marrow, they circulate for our lifetime)
It is the rib cage (thoracic cage)
Exactly 989527/1048576, or approximately 94.37%
Since each trait is carried on a different chromosome, the two traits are independent of each other. Since both parents are heterozygous for the trait, each parent can contribute 1 of a possible 4 combinations of the alleles. So there are 16 possible offspring. I'll use "a", "A", "b", "B" to represent each allele and the possible children are aabb, aabB, aaBb, aaBB, aAbb, aAbB, aABb, aABB, Aabb, AabB, AaBb, AaBB, AAbb, AAbB, AABb, and AABB
Of the above 16 possibilities, there are 7 that are homozygous in an undesired traint and 9 that don't exhibit the undesired trait. So let's first calculate the probability of "what are the chances that all 5 children not exhibiting an undesired trait?" and then subtract that result from 1. So
1-(9/16)^5 = 1 - 59049/1048576 = 989527/1048576 which is approximately 0.943686485 = 94.3686485%
So the answer is exactly 989527/1048576, or approximately 94.37%
Answer:
A,C E
Explanation:
The inner membrane of the mitochondria separate the matrix of the mitochondria from the cytosol(inner membrane space.). It is invaginated folded inwards to form the critae. This is an adaptive feature to increase the surface area for biochemical reaction in the mitochondria.
The invagination gives two compartments the inner mitochondria also creates the outer intermembrane space and the inner matrix
These are the substances that can pass freely the inner membrane of the mitochondria.Pyruvate and H+ can not pass through.Specifically,it is not preamble to H+ because, hydrogen ions are needed to generate the electrochemical gradients needed for the chemical energy for phosphorylation of ADP by P to form ATPs by the enzyme ATPase synthase.If the inner membrane is permeable to H+ the electochemical gradient will not be produced, and therefore ATPs productions stops.
O2 needs to pass through the inner membrane because it it the final electron acceptor. Therefore if not allowed to pass through oxidative phosphorylation and ETC will nor occur.
CO2 must pass through because its accumulation will increase the acidity of the inner mitochondria
