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UkoKoshka [18]
2 years ago
8

If anyone could complete this timeline in order, left to right, that'd be much appreciated :)

Biology
2 answers:
Lady_Fox [76]2 years ago
6 0

Explanation:

if anyone could complete this timeline in order, left to right, that'd be much appreciated :)

hope it is helpful to you

arlik [135]2 years ago
5 0
I’m afraid the timeline was forgotten, but no matter it is the thought that counts right!

I wanted to pop on to say, I hope you all have an amazing day, and found something to make you smile today! Make sure to take mental health breaks!
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How are the hydrogen bonds in water responsible for many of the molecules unique characteristics?
DiKsa [7]

Hydrogen bonds exhibit the stronger intermolecular force, and water is a polar molecule, so the hydrogen bonding create strong forces which take more energy to break (causing the surface tension of water), and due to the polarity water molecules “stick” to one another which causes the edges to rise up in a tube, forming a meniscus

8 0
3 years ago
. For thermometers to read temperatures correctly, they must be
allsm [11]

anwser:

A

Explanation:

calibrated to test and see if the temperature correctly

4 0
3 years ago
Read 2 more answers
Etrrthklhjaebirgipbjuefgnijpoaenoebeb
lyudmila [28]

Answer:

very cool, Chris

Explanation:

8\\ \lim_{n \to \infty} a_n x^{2}  \lim_{n \to \infty} a_n

6 0
3 years ago
A tube that contains xylem and phloem​
pshichka [43]

Answer:

a stem

Explanation:

Plants have tubes that run through their stems and roots. These tubes carry water, minerals, and sugars. There are two types of tubes: xylem and phloem.

8 0
3 years ago
A proton has a speed of 3.0 × 106 m/s in a direction perpendicular to a uniform magnetic field, and the proton moves in a circle
jeyben [28]

Answer:

The magnitude of the magnetic field is 0.156 T.

Explanation:

Given that,

Speed of a proton, v=3\times 10^6\ m/s

Radius of the circular path, r = 0.2 m

When the proton enters in the circular path, the centripetal force is balanced by the magnetic force such that :

\dfrac{mv^2}{r}=qvB\sin\theta

q is the charge on proton

Here, \theta=90^{\circ}

\dfrac{mv^2}{r}=qvB\\\\B=\dfrac{mv}{qr}\\\\B=\dfrac{1.67\times 10^{-27}\times 3\times 10^6}{1.6\times 10^{-19}\times 0.2}\\\\B=0.156\ T

So, the magnitude of the magnetic field is 0.156 T. Hence, this is the required solution.

3 0
3 years ago
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