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I believe the answer is squamous cell carcinoma
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Answer:
b. laminar flow
the reynold number is 1329.26
Explanation:
Re = (V x D x ρ)/ η
where,
V = mean velocity = 15.9 cm/s = 0.159m/s
D = vessel diameter = 2.15cm = 0.0215m
ρ = blood density = 1050 kg/m3 = 0.00105 kg/cm3
η = dynamic viscousity= 2.70 × 10-3 Pa·s = 2.70 × 10-3 kg/m-s
applying the formular to calculate for reynolds number, Re =
Re = (V x D x ρ)/ η
=(0.159 x 0.0215 x 1050) / 2.70 × 10-3
=3.589/0.0027 = 1329.26
the Reynolds number for the blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 × 10-3 Pa·s, a density of 1050 kg/m3, and travels at a mean fluid velocity of 15.9 cm/s is 1329.26
which flow through the aorta in a Laminar flow
Note that
a) turbulen= Re >4000
b) laminar= Re <2300
c) transitioning between laminar and turbulen= Re between 2100 and 4000
Answer:
Diffusion describes the movement of particles from an area of higher to lower concentration. That is what the ink is doing when it spreads throughout the jelly. Osmosis only occurs across a semipermeable membrane.
Three domains and six kingdoms