The slope for is JK 1/3 , the slope of LK is -2 , the slope of ML is 2/5 , and the slope of MJ is 3/2 . Quadrilateral JKLM is not a parallelogram because neither pair of opposite sides is parallel
Further explanation:
Given vertices are:
J(−4, 1) , K(2, 3) , L(5, -3) , and M(0, −5) .
We have to find the slopes before concluding any result
The formula for slope is:

So:
<u>Slope of JK:</u>

<u>Slope of LK:</u>

<u>Slope of ML:</u>

<u>Slope of MJ:</u>

As the slopes of all sides are different, the given quadrilateral is not a parallelogram because in order for the quadrilateral to be a parallelogram the opposite sides have to be parallel i.e. have equal slopes and there are no sides with equal slopes.
Keywords: Parallelogram, Quadrilateral
Learn more about quadrilateral at;
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It’s D, when lines are perpendicular, the slopes of the lines are opposite reciprocals.
Answer:
The variable, y is 11°
Step-by-step explanation:
The given parameters are;
in triangle ΔABC;
in triangle ΔFGH;
Segment
= 14
Segment
= 14
Segment
= 27
Segment
= 19
Segment
= 19
Segment
= 2·y + 5
∡A = 32°
∡G = 32°
∡A = ∠BAC which is the angle formed by segments
= 14 and
= 19
Therefore, segment
= 27, is the segment opposite to ∡A = 32°
Similarly, ∡G = ∠FGH which is the angle formed by segments
= 14 and
= 19
Therefore, segment
= 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;
≅
by Congruent Parts of Congruent Triangles are Congruent (CPCTC)
∴
=
= 27° y definition of congruency
= 2·y + 5 = 27° by transitive property
∴ 2·y + 5 = 27°
2·y = 27° - 5° = 22°
y = 22°/2 = 11°
The variable, y = 11°
195.638
that's some weird logic but ok