Answer:
$21
Step-by-step explanation:
21+42=63
x=63:3
x=$21
Answer:

Step-by-step explanation:

» Collect second degree terms (x² coefficients) together and first degree terms (x coefficients) and constants

Answer:
-16
Step-by-step explanation:
(-3 + (-5))(-3 - (-5))
(-3 - 5)(-3 + 5)
(-8)*2
<u>-16</u>
Answer:

Step-by-step explanation:
If the population increases at a rate of 4% per annum, then:
In year 1:

Where
is the initial population and
is the population in year n
In year 2

It can also be written as:

Taking out common factor

Taking out common factor (1 + 0.04)

Taking out again common factor 
Simplifying

So

This is the equation that represents the population for year n
Then, in 4 years, the population will be:

Answer:
Bc = √63 ft
Step-by-step explanation:
Here, we want to get the length of BC
As we can see, there is a right angled triangle ABC, with 12ft being the hypotenuse and 9 ft the other side
So we want to get the third leg which is BC
we can use the Pythagoras’ theorem here
And that states that the square of the hypotenuse equals the sum of the squares of the two other sides
let the missing length be x
12^2 = x^2 + 9^2
144 = x^2 + 81
x^2 = 144-81
x^2 = 63
x = √63 ft