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goldfiish [28.3K]
3 years ago
9

Which of the following is the simplest form of this expression?

Mathematics
2 answers:
hjlf3 years ago
6 0

Answer:

Simplest form is a^{\frac{2}{15} }.

Step-by-step explanation:

Given : \frac{\sqrt[5]{a^{4}}}{\sqrt[3]{a^{2}}}.

To find : Which of the following is the simplest form of this expression?

Solution: We have given :

\frac{\sqrt[5]{a^{4}}}{\sqrt[3]{a^{2}}}

By the radical rule \sqrt[a]{b^{c} } = b^{\frac{c}{a}},

Then

\frac{\sqrt[5]{a^{4}}}{\sqrt[3]{a^{2}}}  = \frac{a^{\frac{4}{5}}}{a^{\frac{2}{3}}}.

⇒a^{\frac{4}{5} -\frac{2}{3}}.

⇒ a^{\frac{12-10}{15} }.

⇒ a^{\frac{2}{15} }.

Therefore, Simplest form is a^{\frac{2}{15} }.

Readme [11.4K]3 years ago
4 0
The numerator could be written a⁴/⁵

The denominator could be written a²/³


Now solve  ( a⁴/⁵) / (a²/³) ==> a⁽⁴/⁵ ⁻²/³)  = a⁽²/¹⁵)

This is the simplest way
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Step-by-step explanation:

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3 years ago
Select the correct answer.
Andrej [43]

Answer:

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3 years ago
Motor vehicles sold to individuals are classified as either cars or light trucks (including SUVs) and as either domestic or impo
Rudik [331]

Answer:

a) Probability that vehicle is Light Truck is 0.69

b) Probability that vehicle is imported car is 0.08 or 8%.

Step-by-step explanation:

Part a)

Event that vehicle is a car is given by A. Since, the vehicles can only be classified as cars or light trucks, the event that a vehicle will be light truck will be compliment of A.

i.e. Event that vehicle is a Light Truck = A^{c}

It is given that in recent year 69% of vehicles sold were light trucks, 78% were domestic, and 55% were domestic light trucks.

So, from here we can say that, if a vehicle is randomly selected from all the vehicles the probability that it would be a light truck will be:

P(Vehicle will be Light Truck) = P(A^{c}) = 69% = 0.69

Part b)

Event that vehicle is imported is given by B. We need to find the probability the a randomly chosen vehicle is an imported car i.e. we have to find probability of occurrence of events A and B together, which will be denoted as: P(A and B)

Since, P(A^{c}) = 69% = 0.69

P(A) = 1 - P(A^{c}) = 1 - 0.69 = 0.31

It is also given that 78% of vehicles were domestic. This means, the percentage/probability of imported vehicles is:

P(B) = 1 - 0.78 = 0.22

55% of vehicles were domestic light trucks. This can be expressed as:

P(A^{c}\&B^{c}), the compliment of this event will give us P(A or B).

i.e.

P(A or B) = 1 - P(A^{c} \&B^{c}) = 1 - 0.55 = 0.45

According to the addition rule of probabilities:

P(A or B) = P(A) + P(B) - P(A and B)

Substituting the calculated values gives us:

0.45 = 0.31 + 0.22 - P(A and B)

P(A and B) = 0.08

This means, the probability that vehicle is imported car is 0.08 or 8%.

4 0
3 years ago
Solve for x...........................................
Lilit [14]

Answer:

x = 12

Step-by-step explanation:

The exterior angles of any polygon always add up to 360, so:

5x+4+4x+9+7x+4+9x-6+4x+1=360\\29x+12=360\\29x = 348\\x = 12

4 0
3 years ago
4 solid cubes were made out of the same material. All four have different side lengths: 6cm, 8cm, 10cm, and 12cm. How to distrib
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Answer:

The volumes of the cubes are 6³ = 216, 8³ = 512, 10³ = 1,000 and 12³ = 1,728 for a combined volume of 216 + 512 + 1,000 + 1,728 = 3456 which means that each side of the scale must have a combined volume of 3456 / 2 = 1728. This means that in order for the scale to be balanced we need to put the 12 cm cube on one side and the other 3 cubes on the other side.

8 0
3 years ago
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