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3 years ago

How does the standard deviation help you to determine concentration of the data and whether or not there are potential outliers?

1 answer:

5 0

I believe that the answer to the question provided above is that standard deviation in definition is how scattered the data are, thus it will determinr possible outliers.
Hope my answer would be a great help for you. If you have more questions feel free to ask here at Brainly.

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Consider the series 3/2 + 3/4 + 3/8 + 3/16 + ... What expression defines Sn?

snow_lady [41]

For the series 3/2 + 3/4 + 3/8 + 3/16 + ...the sum will be calculated by the formula $3(\dfrac{1}{2})^n$ .

<h3>What is number series?</h3>

When the numbers are arranged in a series with some logic then it is called as the number series.

here we have a series:

$\dfrac{3}{2}+\dfrac{3}{4}+\dfrac{3}{8}+\dfrac{3}{16}+............$

The sum of the series will be given as:

$S_n=3(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+............)$

$S_n=3 (\dfrac{1}{2})^n$

Hence for the series 3/2 + 3/4 + 3/8 + 3/16 + ...the sum will be calculated by the formula $3(\dfrac{1}{2})^n$

To know more about number series follow

brainly.com/question/6561461

#SPJ1

5 0

2 years ago

7-x=-2<br><br> find the variable

nevsk [136]

Answer:

Step-by-step explanation:

7-x=-2

-x=-2-7

-x=-9

x=9

7 0

3 years ago

Use the divergence theorem to calculate the surface integral ??s f · ds; that is, calculate the flux of f across s. f(x,y,z = x2

Ymorist [56]

By the divergence theorem, the surface integral given by

$\displaystyle\iint_{\partial S}\mathbf F\cdot\mathbf n\,\mathrm dS$

(where the integral is computed over the entire boundary of the surface) is equivalent to the triple integral

$\displaystyle\iiint_R\nabla\cdot\mathbf F\,\mathrm dV$

where $V$ is the volume of the region $R$ bounded by $\partial S$ .

You have

$\mathbf F(x,y,z)=x^2y\,\mathbf i+xy^2\,\mathbf j+4xyz\,\mathbf k$
$\implies \nabla\cdot\mathbf F=\dfrac{\partial}{\partial x}[x^2y]+\dfrac{\partial}{\partial y}[xy^2]+\dfrac{\partial}{\partial z}[4xyz]=8xy$

and so the integral reduces to

$\displaystyle8\int_{x=0}^{x=5}\int_{y=0}^{y=1}\int_{z=0}^{z=5-x-5y}xy\,\mathrm dz\,\mathrm dy\,\mathrm dx=-\dfrac{250}3$

7 0

4 years ago

What is the area of a sector of a circle with a radius of 6 inches and formed by a central angle that measures 90°?

trapecia [35]

$\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ \theta =90\\ r=6 \end{cases}\implies A=\cfrac{(90)(\pi )(6)^2}{360} \\\\\\ A=\cfrac{3240\pi }{360}\implies A=9\pi \implies A\approx 28.2743$

8 0

4 years ago

Read 2 more answers

Find the distance between (4, -5) and (-4, -5) on the coordinate plane

kirill [66]

Answer:

x difference is 8

Step-by-step explanation:

Y values are the same so just find the difference in -4 and 4

7 0

4 years ago