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mezya [45]
2 years ago
5

EXPONENTIAL FUNCTIONS HELP Write the function for each graph described below. the graph of f(x) = 2x reflected across the x-axis

. The graph of f(x)= 1/3x translated up 5 units. The graph of f(x) = 3x left 2 units, and down 3. The graph of f(x) = 1/2x translated down 2 units. The graph of f(x) = 4x stretched horizontally by a factor of 3. The graph of f(x) = 2x up 4 units, right 3.
Mathematics
1 answer:
raketka [301]2 years ago
7 0

Answer:

  • -2^x
  • (1/3)^x +5
  • 3^(x +2) -3
  • (1/2)^x -2
  • 4^(x/3)
  • 2^(x -3) +4

Step-by-step explanation:

In general, the transformation ...

  g(x) = f(x -h) +k

translates f(x) right h units and up k units.

The transformation ...

  g(x) = f(x/a)

stretches the graph horizontally by a factor of "a".

The transformation ...

  g(x) = -f(x)

causes the graph to be reflected over the x-axis.

___

Applying the above, we have ...

f(x) = 2^x reflected over x is g(x) = -2^x

f(x) = (1/3)^x translated up 5 is g(x) = (1/3)^x +5

f(x) = 3^x translated by (-2, -3) is g(x) = 3^(x +2) -3

f(x) = (1/2)^x translated down 2 is g(x) = (1/2)^x -2

f(x) = 4^x stretched horizontally by a factor of 3 is g(x) = 4^(x/3)

f(x) = 2^x translated by (3, 4) is g(x) = 2^(x -3) +4

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HELPPP!!!! Both questions are incredibly confusing to me !!!!!
Darya [45]

Answer:

Step-by-step explanation:

I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.

Problem 3 depends on getting RS = RW.

RT = RT                                    Reflexive property

<STR = <WTR                           A straight line having 1 rt angle  actually has 2

ST = TU                                    They are marked as equal

Triangle STR=Triangle WTR    SAS

RS = RW                                    Corresponding parts of = triangles are =

8x = 6x + 5                                Subtract 6x from both sides

8x -6x = 6x - 6x + 5                   Combine

2x = 5                                         Divide by 2

2x/2 = 5/2

x = 2.5

RU = 6*2.5 + 5

RU = 15 + 5

RU = 20

Now we can play with Question 4.

This question depends on the method used in three, although not entirely.

What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.

Directions

Make RT longer. Draw down and to your right.

Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.

Draw UW.

Label UW as 8

Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8

TW = TW                        Reflexive

<UTW = STW                 Same reason as in 3. UtW is a right angle

UT = ST                          Given (the marking tells you so.

ΔUTW = ΔSTW              SAS

UW = SW                       Corresponding parts of = triangles are =

SW  = 8

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2 years ago
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Answer:

a) 450. b) 1:1.25 c) 32 rooms

Step-by-step explanation:

1. 100*4.5 = 450

2. 16:20 divide by 4 -> 4:5  (simplifies to 1:1.25)

3. 64/2 = 32 rooms needed. They have 16.

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Answer:

a) The slope of the function is 3.

c) The equation is represented by n(t) = 3\cdot t + 35.

d) The y-intercept of the function is 35.

Step-by-step explanation:

a) According to the statement, we must assume that number of pieces of mail that must be hand-sorted (dependent variable) is represented by a linear function in terms of time (independent variable). That is:

n(t) = m\cdot t + n_{o} (1)

Where:

m - Slope, measured in number of pieces per minute.

t - Time, measured in minutes.

n_{o} - Initial number of pieces of mail that must be hand-sorted (y-intercept), measured in pieces.

n - Current number of pieces of mail that must be hand-sorted, measured in pieces.

From Geometry, we know that a line can be formed by know two distinct points. If we know that n(15\,min) = 80\,p and n(45\,min) = 170\,p, then the following system of linear equations is formed:

15\cdot m + n_{o} = 80 (2)

45\cdot m + n_{o} = 170 (3)

The solution of the system of equations is:

m = 3 and n_{o} = 35

The slope of the function is 3.

c) By (1) and using results from a) we conclude that the equation function is:

n(t) = 3\cdot t + 35 (4)

d) The y-intercept of the function is 35.

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