Question: If the subspace of all solutions of
Ax = 0
has a basis consisting of vectors and if A is a matrix, what is the rank of A.
Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.
Assume: The number of vectors is 3, and the dimension is 5 × 8.
Answer:
The rank of the matrix A is 5.
Step-by-step explanation:
In the standard basis of the linear transformation:
f : R^8 → R^5, x↦Ax
the matrix A is a representation.
and the dimension of kernel of A, written as dim(kerA) is 3.
By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.
That is:
rank(A) = dim(R^8) - dim(kerA)
= 8 - 3
= 5
Hello,
Answer:
1) given equation
2) distributive property
3) combing like terms
4)addition or subtraction property of equality
5) multiplication or division property of equality
Explanation:
Hope this helps!
Answer:
or
5.32cm correct to 2 decimal places
Step-by-step explanation:
This is a right angled triangle from what I know so we have to apply pythagoras theorem.
we need to rearrange this to find a²
This can either be written as a fraction or decimal.
OR
correct to 2 decimal places
$40/12 = unit rate simplify = 10/3
$10/3 per book
18 * 10/3 = $60 for 18 copies
Answer: yes kevin skied as long as lori
