61 quaters
fa;skhdkjfdljiofofjk;anddada
<span>Area of circular metal=πr^2
=3.14 x 3.5 x 3.5 m^2
now,
total cost=area x rate
=3.14 x 3.5 x 3.5 x 3.25 $
=125.01 $</span>
Let's solve your inequality step-by-step.
−12x−0.4>0.2(36.5x+80)−55
Step 1: Simplify both sides of the inequality.
−12x−0.4>7.3x−39
Step 2: Subtract 7.3x from both sides.
−12x−0.4−7.3x>7.3x−39−7.3x
−19.3x−0.4>−39
Step 3: Add 0.4 to both sides.
−19.3x−0.4+0.4>−39+0.4
−19.3x>−38.6
Step 4: Divide both sides by -19.3.
−19.3x
−19.3
>
−38.6
−19.3
x<2
Answer:
x<2
1 dozen = 12
Divide 941 by 12:
941 / 12 = 78.42
So the greatest number of dozens he can make is 78.
