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3 years ago

Formula for finding prime numbers

1 answer:

6 0

There is no formula for finding prime numbers. The rule is just if a number is prime then it is divisible by 1 and itself

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F(x) = ax2 - 12, g(x) = 2x +3, and f(3) = 24. What<br> is the value of g(f(2)) ?

elixir [45]

<h2>Answer: g(f(2)) = 11</h2>

Step-by-step explanation:

g(f(2)) is substituting the value of f(2) for x in g(x). But we must first find f(2).

We know that f (x) = ax² - 12

Since f(3) = 24

⇒ a(3²) - 12 = 24

9 a = 36

a = 4

∴ f(2) = (4)(2²) - 12

= 4

⇒ g(f(2)) = 2(4) + 3

= 11

6 0

2 years ago

Read 2 more answers

Solve for x.<br> -x/3=2<br><br> x= -6<br> x= -1<br> x = 6

LenKa [72]

Answer:

x = -6

Step-by-step explanation:

Solve for x:

-x/3 = 2

Multiply both sides of -x/3 = 2 by -3:

(-3 (-x))/3 = -3×2

-3×(-1)/3 = (-3 (-1))/3:

(-3 (-1))/3 x = -3×2

(-3)/3 = (3 (-1))/3 = -1:

--1 x = -3×2

(-1)^2 = 1:

x = -3×2

-3×2 = -6:

Answer: x = -6

6 0

3 years ago

A checking account is overdrawn if it has a negative balance. Marc’s account is overdrawn by $63. What will the balance be after

miss Akunina [59]

(-63 + 173) - 41 = ?
110 - 41 = 69.

6 0

3 years ago

What is the simplified form of the following expression?

USPshnik [31]

Option C:

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

Solution:

Given expression is

$$\sqrt[3]{\frac{4 x}{5}}$

Note: $\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5$

To find the correct expression for the above simplified expression.

Option A: $\frac{\sqrt[3]{4 x}}{5}$

5 can be written as $\sqrt[3]{125}$ .

$$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{4x}{125} }$

It is not the given simplified expression.

Option B: $\frac{\sqrt[3]{20 x}}{5}$

$$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{20x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4x}{25} }$

It is not the given simplified expression.

Option C: $\frac{\sqrt[3]{100 x}}{5}$

$$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{100x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4 x}{5}}$

It is the given simplified expression.

Option D: $\frac{\sqrt[3]{100 x}}{125}$

$$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}$

It is not the given simplified expression.

Hence Option C is the correct answer.

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

3 0

3 years ago

Steve puts an 18-foot ladder against his house. The ladder reaches a height of 15 feet on the house. How far is the bottom of th

krek1111 [17]

Answer:

$3 \sqrt{11}$

Step-by-step explanation:

Since we are given the hypotenuse which is 18 since it slanted, and leans on the house. And we are given one of the legs which is 15 since it is vertical. We can use the pythagorean theorem to solve for this problem.

${a}^{2} + {b}^{2} = c {}^{2}$

where a and b are the legs and c is the hypotenuse l.

Let plug it in

${a}^{2} + 15 {}^{2} = {18}^{2}$

${a }^{2} + 225 = 324$

${a}^{2} = 99$

$a = \sqrt{99}$

$a = \sqrt{9 \times 11}$

$a = 3 \sqrt{11}$

4 0

3 years ago