Ask question

Ask question

All categories

3 years ago

5

The pool at "Splash Around" is open for 14 weeks during the summer. You can swim for $6 a session, or you can buy a membership f

or $100 and pay only $4 a session. Which equation would you use to determine how many sessions you must use the pool to justify buying the membership? A) 4x = 100 + 6x B) 6x + 4x = 100 C) 6x = 100 + 4x D) 100 - 4x = 6x

2 answers:

shutvik [7]3 years ago

8 0

C) 6x=100+4x
This is because since you need to justify buying a membership, you would try and equal the prices between not having a membership which is 6x and having a membership which is 100+4x

Yanka [14]3 years ago

7 0

Answer:

C) $6x=100+4x$

Step-by-step explanation:

Let the number of sessions be x

Let the total payment be y

Without membership, the equation becomes:

$y=6x$

With membership, the equation becomes:

$y=100+4x$

Now to justify, $100, we will equal both to get the number of sessions.

$6x=100+4x$

$=> 2x=100$

Dividing both sides by 2;

x = 50

Hence, the right equation is : $6x=100+4x$

You might be interested in

What would happen to the slope of the graph of y=2/3×-3 if the line were shifted 6 units up?

yaroslaw [1]

The slope wouldn't change, but the y-intercept would become 3 because you add -3 to 6

5 0

2 years ago

How do you find the leg of a triangle?

Law Incorporation [45]

If it is right triangle use pythagorean

4 0

3 years ago

Garth has a summer job and earns $9.32 per hour. One week, he works 16 34 3 4 hours. He deposits $150 in a bank and decides to u

trasher [3.6K]

Answer:

762 raffle tickets

Step-by-step explanation:

16×9.32= 149.12

34×9.32= 316.88

3×9.32= 27.96

4×9.32= 37.28

add them all up= 531.24

531.24-150=381.24

381.24÷.50=762.48

answer: 762 raffle tickets

5 0

3 years ago

A potter use 4/5 of a pound of clay to make a bowl.How many bowls can the potter make from 12 pounds.

Aleksandr [31]

12/1 / 4/5=

12/1 * 5/4 =

60/4 = 15

they can make 15 bowls

8 0

3 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

a.

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

b.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

c.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

d.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

e.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

2 years ago