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2 years ago

2 of the dozen eggs in a cartoon are cracked about what percent of the carton is not cracked

Mathematics

2 answers:

jek_recluse [69]2 years ago

8 0

since there are a total of 30 eggs in a carton and 2 dozen are broken (24) it'd be 20% that isn't broken

pychu [463]2 years ago

4 0

well, a carton has a dozen, namely 12 or the 100%, two were cracked.

if we know 12 is the 100%, what is 2 off of it in percentage?

$\bf \begin{array}{ccll}
amount&\%\\
\cline{1-2}
12&100\\
2&x
\end{array}\implies \cfrac{12}{2}=\cfrac{100}{x}\implies x=\cfrac{2\cdot 100}{12}\implies x=16.\overline{66}$

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Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

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$P(2) = \frac{n(2)}{n(s)}$

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$P(2) = \frac{1}{2}$

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$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

We can conclude that the change to the face 3 affects the value of P(Odd Number)

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On picture day, 3 times as many girls wore dresses rather than pants. If there are 12 girls in the class, how many wore a dress?

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Answer:

Step-by-step explanation:

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