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inna [77]
3 years ago
9

"At an ice cream shop, customers pay $3.00 for a medium ice cream plus $0.75 per topping. At a second ice cream shop, customers

pay $5.25 for a medium ice cream plus $0.25 per topping. How many toppings would a customer have to order for the ice cream to cost the same at either shop?"
Mathematics
1 answer:
baherus [9]3 years ago
8 0

Answer:

3 would be required to break even.

Step-by-step explanation:

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I forgot how to do this​
adoni [48]

Answer:

\boxed{ \bold{  \huge{ \boxed{ \sf{1}}}}}

Step-by-step explanation:

\sf{ \frac{1}{2}  \times 2}

Multiply the numerators for the numerator and multiply the denominators for its denominator and reduce the fraction obtained after multiplication into lowest term.

\dashrightarrow{ \sf{ \frac{1 \times 2}{2 \times 1} }}

\dashrightarrow{ \sf{ \frac{2}{2} }}

\dashrightarrow{ \sf{1}}

Or, You can simply reduce the fraction with 2, which results to 1.

Hope I helped!

Best regards! :D

6 0
3 years ago
Write a three digit number that is divisible by 6<br>​
FinnZ [79.3K]

Answer:150

Step-by-step explanation:

7 0
3 years ago
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jonathan worked at McDonald's 20 hours per week and earned 192 $ use the equation 20h =195 to find Johnathan hourly wage..
Gre4nikov [31]
His hourly wage should be 9.75
5 0
3 years ago
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How do you get 27 only using the numbers 1,2,3,4
Elanso [62]
If you multiply 3 and 3 and 3 
5 0
3 years ago
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Which of these values for p and a will cause the function f(x)=Pax to be an exponential growth function
vovikov84 [41]

The option are missing in the question. The options are :

A.  P = 2, a = 1

B.  $P=\frac{1}{2} ;  a =\frac{1}{3}$

C. $P=\frac{1}{2} ;  a =1$

D. P = 2, a = 3

Solution :

The given function is $f(x)= Pa^x$

So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.

When the four option being substituted in the function, we get

A). It is a constant function since $2(1^x)=2$

B). Here, the value of a is a fraction which is less than 1, so it is a decay function. $f(x)=\frac{1}{2}\left(\frac{1}{3}\right)^x$

C). It is a constant function since the value of a is 1.

D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.

  $f(x)=2(3)^x$

Therefore, option (D). represents an exponential function.

4 0
2 years ago
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