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Tamiku [17]
3 years ago
7

Just Answer 8 and plz help

Mathematics
1 answer:
zavuch27 [327]3 years ago
5 0

number 9 is a

number 8 is b


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Sara bought a 25-ounce jar of strawberry jam for $4.50. What is the unit price?
fgiga [73]
$0.18 is the answer. How I got it was you do $4.50 over 25 ounces. Then divide the $4.50 by 25. You should get 0.18
7 0
3 years ago
Does this table of values represent a linear relationship? Explain your answer.
eduard

Answer:

Yes

Step-by-step explanation:

Yes, because there is a constant rate of change. It is and will always be constantly increasing by 1.5.

To be a linear line you have to have a constant rate of change.

7 0
3 years ago
134 A financial analyst believes that if interest rates decrease in a given period then the
lawyer [7]

The probability that the market will go up and interest rate will go down during the period in question is 0.03.

<h3>What is the probability?</h3>

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability that the market will go up and interest rate will go down  = 0.08 X 0.40 = 0.03

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

5 0
2 years ago
At a coffee sale held one day in 2004 ,the average price of 50 kg bag of coffee was sh 2422.90 . What was the cost of 1 kg of co
gregori [183]

Answer: $ 48.46

Step-by-step explanation:

If the price of 50 Kg of coffee was 2422.99, what is the cost of 1 Kg of coffee?

50/1 = 2422.90/x (cross multiplication)

48.46

4 0
3 years ago
Water whose temperature is at 100∘C is left to cool in a room where the temperature is 60∘C. After 3 minutes, the water temperat
Tju [1.3M]

Answer:

21.68 minutes ≈ 21.7 minutes

Step-by-step explanation:

Given:

T=60+40e^{kt}

Initial temperature

T = 100°C

Final temperature = 60°C

Temperature after (t = 3 minutes) = 90°C

Now,

using the given equation

T=60+40e^{kt}

at T = 90°C and  t = 3 minutes

90=60+40e^{k(3)}

30=40e^{3k}

or

e^{3k}=\frac{3}{4}

taking the natural log both sides, we get

3k = \ln(\frac{3}{4})

or

3k = -0.2876

or

k = -0.09589

Therefore,

substituting k in 1 for time at temperature, T = 65°C

65=60+40e^{( -0.09589)t}

or

5=40e^{( -0.09589)t}

or

e^{( -0.09589)t}=\frac{5}{40}

or

e^{( -0.09589)t}=0.125

taking the natural log both the sides, we get

( -0.09589)t = ln(0.125)

or

( -0.09589)t = -2.0794

or

t = 21.68 minutes ≈ 21.7 minutes

6 0
3 years ago
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