Answer:
<h2>
3,654 different ways.</h2>
Step-by-step explanation:
If there are 30 students in a class with natasha in the class and natasha is to select four leaders in the class of which she is already part of the selection, this means there are 3 more leaders needed to be selected among the remaining 29 students (natasha being an exception).
Using the combination formula since we are selecting and combination has to do with selection, If r object are to selected from n pool of objects, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
Sinca natasha is to select 3 more leaders from the remaining 29students, this can be done in 29C3 number of ways.
29C3 = 29!/(29-3)!3!
29C3 = 29!/(26!)!3!
29C3 = 29*28*27*26!/26!3*2
29C3 = 29*28*27/6
29C3 = 3,654 different ways.
This means that there are 3,654 different ways to select the 4 leaders so that natasha is one of the leaders
All of the numbers are the mode, so it is
1982, 1988, 1989, 1994, 1995, 2005
The interval notation is 
Explanation:
The inequality is 
Let us complete the square, we get,
Simplifying, we have,
Adding both sides of the equation by 11, we get,
Since, we know that for 
, if n is even then ![-\sqrt[n]{a}](https://tex.z-dn.net/?f=-%5Csqrt%5Bn%5D%7Ba%7D%3Cu%3C%5Csqrt%5Bn%5D%7Ba%7D)
Thus, writing the above expression in this form, we get,
Also, if 
then 
and 
Then ,we have,
and 
Solving the inequalities, we get,
and 
Merging the intervals, we have,
Hence, writing the solution in interval notation, we have,
Therefore, the answer is
There are 3 terms in this expression. You can determine this answer by knowing that terms are either a single number or variable or numbers and variables multiplied together. Here's a picture example below:
Hope it helps! Mark as brainliest!
