If a fair die is rolled 3 times, what is the probability, to the nearest thousandth, of getting exactly 0 twos?

1 answer:

5 0

The answer is .578 you just do 5/6 due to the fact that there are 6 sides on a die and 1 side is a 2 so if you don’t get a two there is 5 sides left so you do 5/6 to the power of 3 leaving you with .578 and some

You might be interested in

What is the product of 119 thousandths times 10?

Gnesinka [82]

The answer is A becaues 119 thousand times 10 equals 1190000
then you divide it by 100 to get A.119 hunderths

3 0

3 years ago

Read 2 more answers

a phone company offers two monthly plan. plan a costs $30 plus an additional $0.14 for each minute of calls. plan b costs $8 plu

Inessa05 [86]

What’s the question

4 0

3 years ago

Answer the question on the image underneath

Nadya [2.5K]

Answer:

I think it's A. sorry if i'm wrong.

Step-by-step explanation:

8 0

3 years ago

Which number is eqyal to 13

Ostrovityanka [42]

Answer:
XIII

Hope this helps

6 0

2 years ago

1. Match the polynomial identity to the correct answer.

Katen [24]

Answer:

$a: (a-b)(a+b);b: (a-b)(a^{2}+ab+b^{2}); c: (a^{2} +2ab+b^{2}); d: (a+b)(a^{2}- ab+b^{2})$

Step-by-step explanation:

Given the expressions all that is required is to expand them (using the distributive property) to see which answers they match up to:

For a: $(a-b)(a+b)=a^{2} +ab-ab-b^{2} =a^{2}-b^2$

For b: $(a-b)(a^2+ab+b^2)=a^3+a^2b+ab^2-a^2b-ab^2-b^3=a^3-b^3$

For c calculate the square of a sum: $(a+b)^2=a^2+ab+ab+b^2$

(add like terms) c: $a^2+2ab+b^2$

For d: $(a+b)(a^2-ab+b^2)=a^3-a^2b+ab^2+a^2b-ab^2+b^3$ $=a^3+b^3$

5 0

3 years ago