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SCORPION-xisa [38]
4 years ago
5

What is the area 4 x 5/12

Mathematics
1 answer:
icang [17]4 years ago
8 0

Answer:

1 8/20

Step-by-step explanation:

4/1 X 5/12 20/12 which is 1 8/20

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alexira [117]

The answer would be A and C.

Hope this helps!<3

5 0
3 years ago
Angle ABC is shown . Determine sin B. Write your answer in fraction form.<br><br> Help ASAP
Mkey [24]

Answer:

sin b would be 4/5

Step-by-step explanation:

sine is the opposite leg/the hypotenuse

7 0
3 years ago
find the value of n in each equation. write what n represents in the related division problem 643=4×160+n
schepotkina [342]

Answer: n = 3; n represents a remainder in a division problem.


Explanation:


1) Finding n:


i) Given: 643 = 4 × 160 + n

ii) Do the operations: 643 = 640 + n

iii) Subraction property of the equality: 643 - 640 = n

iv)  Do the operations: 3 = n

Answer: n 3


2) Meaning of n


When you divide 643 by 4 the quotient is 160 and the remainder is 3, because 160 × 4 = 640, and 643 - 640 = 3.


This is, 3 is what is left when you split 643 into 4 getting 160 whole parts (plus the remainder, 3).

3 0
3 years ago
JOURNAL 5.3.4. <br><br> PLZZZ HELP, I NEED 1-9
aniked [119]

Answer:

8?

Step-by-step explanation:

7 0
3 years ago
Use the quadratic formula to solve the following equation -3x^2-x-3=0
tigry1 [53]

<u>Answer:</u>

x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i are two roots of equation -3 x^{2}-x-3=0

<u>Solution:</u>

Need to solve given equation using quadratic formula.

-3 x^{2}-x-3=0

General form of quadratic equation is a x^{2}+b x+c=0

And quadratic formula for getting roots of quadratic equation is

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

In our case b = -1 , a = -3 and c = -3

Calculating roots of the equation we get

\begin{array}{l}{x=\frac{-(-1) \pm \sqrt{(-1)^{2}-4(-3)(-3)}}{2 \times-3}} \\\\ {x=-\frac{1}{6} \pm\left(-\frac{\sqrt{-35}}{6}\right)}\end{array}

Since b^{2}-4 a c is equal to -35, which is less than zero, so given equation will not have real roots and have complex roots.

\begin{array}{l}{\text { Hence } x=-\frac{1}{6}-\frac{\sqrt{35}}{6} i \text { and } x=-\frac{1}{6}+\frac{\sqrt{35}}{6} i \text { are two roots of equation - }} \\ {3 x^{2}-x-3=0}\end{array}

8 0
4 years ago
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