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brilliants [131]

3 years ago

14

if a rifleman averages 8 hits out of 10 shots at a target, what is the probability that he will hit the target in 3 out of 4 sho

ts

1 answer:

ivann1987 [24]3 years ago

3 0

Use binomial distribution

You might be interested in

What does 34 12/27-19 5/6=

Lunna [17]

<span>34 12/27-19 5/6
</span>You may get common denominators.

12*2 = 24
27*2 = 54

5*9=45
6*9 = 54

34 24/54 - 19 45/54
Subtract 19.
15 24/54 - 45/54
14 33/54 = Answer.

4 0

3 years ago

Read 2 more answers

Find the value or measure. Assume all lines that appear to be tangent are tangent. X=

aev [14]

According to the secant-tangent theorem, we have the following expression:

$(x+3)^2=10.8(19.2+10.8)$

Now, we solve for <em>x</em>.

$\begin{gathered} x^2+6x+9=10.8(30) \\ x^2+6x+9=324 \\ x^2+6x+9-324=0 \\ x^2+6x-315=0 \end{gathered}$

Then, we use the quadratic formula:

$x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Where a = 1, b = 6, and c = -315.

$\begin{gathered} x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4\cdot1\cdot(-315)}}{2\cdot1} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36+1260}}{2}=\frac{-6\pm\sqrt[]{1296}}{2} \\ x_{1,2}=\frac{-6\pm36}{2} \\ x_1=\frac{-6+36}{2}=\frac{30}{2}=15 \\ x_2=\frac{-6-36}{2}=\frac{-42}{2}=-21 \end{gathered}$ <h2>Hence, the answer is 15 because lengths can't be negative.</h2>

7 0

1 year ago

Can somebody please help?

kari74 [83]

Step-by-step explanation:

√121 - √-192 - √4 + √-48

= 11 - 192i - 2 + 48i

= 9 - 144i

= 9(1 - 16i).

6 0

3 years ago

On a coordinate plane, quadrilateral Q R S T has points (0, 2), (negative 4, 0), (0, negative 3), and (4, 0).

Afina-wow [57]

By applying the definitions of <em>rigid</em> transformation ((x, y) → (0.5 · x, 0.5 · y)) and dilation, we conclude that the coordinates of Q'(x, y) are (0.1).

<h3>How to apply rigid transformations on a point</h3>

Herein we must apply a rigid transformation into a given point to determine an image. <em>Rigid</em> transformations are transformations applied on a <em>geometric</em> locus such that <em>Euclidean</em> distance is conserved. Dilations are a kind of <em>rigid</em> transformations such that:

(x, y) → (k · x, k · y), for k > 0

If we know that Q(x, y) = (0, 2) and k = 0.5, then the coordinates of Q' are:

Q'(x, y) = (0.5 · 0, 0.5 · 2)

Q'(x, y) = (0, 1)

By applying the definitions of <em>rigid</em> transformation ((x, y) → (0.5 · x, 0.5 · y)) and dilation, we conclude that the coordinates of Q'(x, y) are (0.1).

To learn more on dilations: brainly.com/question/13176891

#SPJ1

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7Bw%7D%7B3%7D%20" id="TexFormula1" ti

ElenaW [278]

Answer: $\bold{w=\dfrac{6y-3}{2}}$

<u>Step-by-step explanation:</u>

Isolate w by performing the following steps

Multiply by 6 on both sides to clear the denominator
Subtract 3 from both sides
Divide both sides by 2

$y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}$

5 0

3 years ago