Answer: 63 degrees (second choice)
The two angles shown are corresponding angles. They are both on the bottom side of their adjacent parallel line, and at the same time, they are also on the left side of the transversal line. This is why they are corresponding angles.
Corresponding angles are congruent if you have a set of parallel lines like the diagram shows. So that's why a = 63.
You need to learn no to copy it kiddo
Answer:
<em>The answer for the first question is: </em>
<em>12/80 =</em>
<em>12 ÷ 80 =</em>
<em>0.15 =</em>
<em>0.15 × 100/100 =</em>
<em>0.15 × 100% =</em>
<em>(0.15 × 100)% =</em>
<h2><em>
15%</em></h2>
<em>Then, the answer for the second question is: </em>
<em>75% × 52 =</em>
<em>(75 ÷ 100) × 52 =</em>
<em>(75 × 52) ÷ 100 =</em>
<em>3,900 ÷ 100 =</em>
<h2><em>
39 </em></h2>
* Hopefully this helps:) Mark me the brainliest:)!!!
The first thing any good mathematician does is convert the measurements to the same unit as what the question is asking. In this problem, it states that the pool fills at a rate of 20 cubic meters per hour. Just keep in mind that an hour is 60 minutes.
The next step is to see how many cubic meters will cost $300. This can be done by dividing 300 by 10. This gets you 30 cubic meters of water.
You already know that 60 minutes is 20 cubic meters of water. That leaves the remaining 10 cubic meters of water. By dividing the rate given, you get that 30 minutes is 10 cubic meters of water. Add the 60 and 30 together to get 90 minutes.
It will take 90 minutes for the pump to use $300.
Answer:
x = 2 cm
y = 2 cm
A(max) = 4 cm²
Step-by-step explanation: See Annex
The right isosceles triangle has two 45° angles and the right angle.
tan 45° = 1 = x / 4 - y or x = 4 - y y = 4 - x
A(r) = x* y
Area of the rectangle as a function of x
A(x) = x * ( 4 - x ) A(x) = 4*x - x²
Tacking derivatives on both sides of the equation:
A´(x) = 4 - 2*x A´(x) = 0 4 - 2*x = 0
2*x = 4
x = 2 cm
And y = 4 - 2 = 2 cm
The rectangle of maximum area result to be a square of side 2 cm
A(max) = 2*2 = 4 cm²
To find out if A(x) has a maximum in the point x = 2
We get the second derivative
A´´(x) = -2 A´´(x) < 0 then A(x) has a maximum at x = 2