Answer: yes because you can save 1/3 of the skittles from the 1/6 of the skittles you didnt eat earlier but idk where the rest of the skittles that you are not saving and didnt eat would go.
Step-by-step explanation: hope this helps :!.
Answer:
The interquartile range is 5.
Step-by-step explanation:
Ah, a throwback to interquartile range... let me help :)
4,5,6,8,9,10,11,12
First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.
The average rate is:
(f(4) - f(1)) / (4 - 1)
The meaning is how much f(x) changes when x increased by 1.
Answer:
Given a general quadratic equation of the form
{\displaystyle ax^{2}+bx+c=0}ax^2+bx+c=0
with x representing an unknown, a, b and c representing constants with a ≠ 0, the quadratic formula is:
{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}\ \ }{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}\ \ }
where the plus–minus symbol "±" indicates that the quadratic equation has two solutions.[1] Written separately, they become:
{\displaystyle x_{1}={\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}\quad {\text{and}}\quad x_{2}={\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}}{\displaystyle x_{1}={\frac {-b+{\sqrt {b^{2}-4ac}}}{2a}}\quad {\text{and}}\quad x_{2}={\frac {-b-{\sqrt {b^{2}-4ac}}}{2a}}}
Each of these two solutions is also called a root (or zero) of the quadratic equation. Geometrically, these roots represent the x-values at which any parabola, explicitly given as y = ax2 + bx + c, crosses the x-axis.[2]
As well as being a formula that yields the zeros of any parabola, the quadratic formula can also be used to identify the axis of symmetry of the parabola,[3] and the number of real zeros the quadratic equation contains.[4]
Step-by-step explanation: