An expression that equals 24 and has to include an exponent

You are interested in conducting a survey at your school to determine if gender or ethnicity is related to perceptions about edu

BigorU [14]

Answers

We can use cluster sampling here. In this case, the population is divided into sampling units or clusters, for example, zone within educational or geographical areas. Having divided the population into clusters, we can use simple random sampling to select the clusters to be examined. Consider Asian American as one cluster, African american as another cluster and so on. According to the size of the cluster randomly select individuals from each cluster for a total of 100 individuals.

Generally there would be bias in accordance to the differnce in ethnicity. Also if the selected students are in a younger, then the teachers opnion would play a very big role there.

The question itself is a source of bias and it seems to give an idea to the students to think in these lines. The question can be better worded to get a correct answer. Even if there is equal opportunity, some students may read the question and give a negative answer.

7 0

3 years ago

Consider the vectors Bold uuequals=left angle 4 comma 0 right angle4,0 and Bold vvequals=left angle negative 3 comma negative 3

saw5 [17]

Answer:

Angle between the two vectors is 135°

u•v = -12

Step-by-step explanation:

Given two vectors u = (4,0) and v = (-3,-3).

To find the angle between the two vectors we will use the formula for calculating the angle between two vectors as shown;

u•v = |u||v|cos theta

cos theta = u•v/|u||v|

theta = arccos (u•v/|u||v|)

u•v = (4,0)•(-3,-3)

u•v = 4(-3)+0(-3)

u•v = -12

For |u| and |v|

|u| = √4²+0²

|u| = √16 = 4

|v| = √(-3)²+(-3)²

|v| = √9+9

|v| = √18

|v| = 3√2

|u||v| = 4×3√2 = 12√2

theta = arccos(-12/12√2)

theta = arccos(- 1/√2)

theta = -45°

Since cos is negative in the second quadrant, theta = 180-45°

theta = 135°

To get u•v using the formula u•v = |u||v|cos theta

Given |u||v| = 12√2 and theta = 135°

u•v = 12√2cos 135°

u•v = 12√2× -1/√2

u•v = -12√2/√2

u•v = -12

For the diagram of the vectors, find it in the attachment below.

4 0

4 years ago

Read 2 more answers

Factor completely:<br> c<br> 2ax^2 –2ay^2

Angelina_Jolie [31]

Step-by-step explanation:

$2a {x}^{2} - 2a {y}^{2} \\ 2a( {x}^{2} - {y}^{2} ) \\ 2a(x - y)(x + y)$

7 0

4 years ago

A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is

katovenus [111]

Answer:

The constant of variation is 4032

Step-by-step explanation:

Given:

Let a rectangle (say A) has length of rectangle(l)= 72 cm and width of rectangle(w) = 56 cm.

Area of rectangle is multiply its length by its width.

Then,

area of rectangle (A) = $l \times w$ = $72 \times 56$ = 4,032 square cm.

It is given that the other rectangle B has the same area as the rectangle A.

Then, the area of rectangle (B) = area of rectangle (A) = 4,032 square cm. .......[1]

First find the length of rectangle B:

Given: width of the rectangle B is 21 cm

then, by definition

Area of rectangle B = $l \times w$ = $l \times 21$

From [1];

4032 = $l \times 21$

Divide 21 both sides we get;

$l =\frac{4032}{21} = 192$ cm

therefore, the length of rectangle B is 192 cm

To find the constant variation:

if y varies inversely as x

i.e, $y \propto \frac{1}{x}$

⇒ $y = \frac{k}{x}$ where k is the constant variation.

or k = xy

As area of rectangle is multiply its length by width.

This is the inversely variation.

as: $l \propto \frac{1}{w}$

or $l = \frac{A}{w}$ where A is the constant of variation

Since, the area (A) of both the rectangles are constant.

therefore, the constant of variation is, 4032

5 0

4 years ago

PLEASEE HELP MAN!! draw a graph that is Vertically stretched by a factor of 2 and Moved 3 units to the right and Moved 2 units d

mixas84 [53]

Answer:

here u go :)

Step-by-step explanation:

7 0

3 years ago