First solve your inequality step by step.
y+15<3
= y<-12
Answer is A. y<-12
Answer will help you.
Brainliest answer and Verified answers.
Answer:
Explanation:
<u>1. Using the minimun number of sheets of paper in the interval [300, 400]</u>
a) Cost: $ 2.00 / 100 sheets
b) 300 sheets / day × $ 2.00 / 100 sheets = $ 6.00 / day
c) Approimately 20 school days per month:
- $ 6.00 / day × 20 day = $ 120.00
<u>2. Using the maximum number of sheets of paper in the interval [300, 400]</u>
a) Cost: $ 2.00 / 100 sheets
b) 400 sheets / day × $ 2.00 / 100 sheets = $ 8.00 / day
c) Approimately 20 school days per month:
- $8.00 / day × 20 day = $ 160.00
<u>3. Middle value:</u>
Calculate the middle value between $160.00 and $120.00
- [$120.00 + $160.00] / 2 = $140.00
Thus, the answer is the option A.
The LCM this question is 13 and 29
For us to find out how many times more expensive is the deli roast compared to the uncooked roast we need to change the units;
cost of 100g=0.221lb is $2.99
cost of 1 lb will therefore be:
1/0.221*2.99
=$13.53/lb
therefore the number of times more expensive the deli roast is compared to uncooked roast is:
[price of 1lb roasted meat]/[price of 1 lb uncooked meat]
=13.53/4.99
=2.7 times
PART A
s = <span>the number of packets of strawberry wafers ;
c = </span><span>the number of packets of chocolate wafers ;
3 </span>× s + 1 × <span>c = 30 ;
s + c = 22 ;
PART B
</span>The method of solving "by substitution"<span> works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
</span>
c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;
