All categories

2 years ago

Evaluate the expression 4b-6d if b=7 and d=3

Mathematics

2 answers:

stepladder [879]2 years ago

5 0

The answer is 10 you plug 7 in for b and 3 in for d and multiply both side together and the subtract

Delicious77 [7]2 years ago

4 0

Answer:

Step-by-step explanation:

4b - 6d = 4*7 - 6*3

= 28 - 18

= 10

You might be interested in

Consider the function represented by 9x+3y= 12 with x as the independent variable. How can this function be written using

Ivenika [448]

Answer:

f(x)=-3x+4

(can't see some of your choices)

Step-by-step explanation:

We want x to be independent means we want to write it so when we plug in numbers we can just choose what we want to plug in for x but y's value will depend on our choosing of x.

So we need to solve for y.

9x+3y=12

Subtract 9x on both sides

3y=-9x+12

Divide both sides by 3:

y=-3x+4

Replace y with f(x).

f(x)=-3x+4

6 0

2 years ago

I need help with this problem 30 points up for grabs if you answer.

Rama09 [41]

Answer:

Step-by-step explanation:

13 cm

7 0

2 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

8 0

2 years ago

SNOG pls help me with my homework

Nataliya [291]

Answer: I think it would costs $34.50 for 7.5 lbs of walnut

Step-by-step explanation: I HOPE THIS HELPS :)

8 0

2 years ago

If you have 7 apples and drop 5 how many do you have left?

kifflom [539]

Answer:

Step-by-step explanation:

7-5=2

6 0

2 years ago

Read 2 more answers