Answer:
please add the attachment of this question
Answer: the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
Step-by-step explanation:
Given data;
lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min
hence, height = 1 / ( 52.0 - 50.0) = 1 / 2
now the probability that the class length is between 50.8 and 51 min = ?
P( 50.8 < X < 51 ) = base × height
= ( 51 - 50.8) × 1/2
= 0.2 × 0.5
= 0.1 ≈ 10%
therefore the probability that the class length is between 50.8 and 51 min is 0.1 ≈ 10%
I can’t see the whole thing take a picture of it again or explain the problem to me
Answer:
10
Step-by-step explanation:
f(x) = 3x + 1
f(3)= 3 * 3 + 1 + 10
Answer:
Average change in temperature each day = 5 degrees/day
Step-by-step explanation:
