Answer:
x=1
y=s
z=1
Step-by-step explanation:
(x, y, z)=(1, 0, 1)
Substitute 0 for y

Confirming if t=0 satisfy the other equation
x = e^−2t cos 4t = e^−2(0)cos(4*0)
= e^(0)cos(0) = 1
z = e^−2t = e^−2(0) = 0
Therefore t=0 satisfies the other equation
Finding the tangent vector at t=0

The vector equation of the tangent line is
(1, 0, 1) +s(0,1,0)= (1, s, 1)
The parametric equations are:
x=1
y=s
z=1
Answer:
1. 8.19, 2. 25.96, 3. 3.95
Step-by-step explanation:
use soh cah toa
1. cos is adjacent/hypotenuse
cos73=x/28
multiply both sides by 28
28cos73=x=8.186
2. sin is opposite over hypotenuse
sin68=x/28
multiply both sides by 28
28sin68=x=25.961
3. sin is opposite over hypotenuse
sin26=x/9
myltiply both sides by 9
9sin26=x=3.945
Answer:
the answer is 1
because 1 is not multiple in our self
Answer:
z = 21 ; y= 16
Step-by-step explanation:
first of all we have to isolate a variable.
In second expression we can obtain:
3y = 2z+6
y = 2/3 z + 2
now we have to substitute this value in the first equation and solve it
8(2/3z+2)-5z = 23
16/3z + 16 -5z = 23
16z +48 - 15z = 69
z = 21
now we have to substitute z in the second equation:
y = 2/3 (21) +2
y = 14+ 2 = 16
y = 16