Answer is (A). (X’ , Y’) = (x, y-6)

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

Now the zero product property tells us that there are two cases where this is true,

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of

, so

where
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which occurs twice in the interval

for

and

. More generally, if you think of

as a point on the unit circle, this occurs whenever

also completes a full revolution about the origin. This means for any integer

, the general solution in this case would be

and

.
<span>Simplifying
12 + -6(w + -3) = 3(-5 + -3w) + 21
Reorder the terms:
12 + -6(-3 + w) = 3(-5 + -3w) + 21
12 + (-3 * -6 + w * -6) = 3(-5 + -3w) + 21
12 + (18 + -6w) = 3(-5 + -3w) + 21
Combine like terms: 12 + 18 = 30
30 + -6w = 3(-5 + -3w) + 21
30 + -6w = (-5 * 3 + -3w * 3) + 21
30 + -6w = (-15 + -9w) + 21
Reorder the terms:
30 + -6w = -15 + 21 + -9w
Combine like terms: -15 + 21 = 6
30 + -6w = 6 + -9w
Solving
30 + -6w = 6 + -9w
Solving for variable 'w'.
Move all terms containing w to the left, all other terms to the right.
Add '9w' to each side of the equation.
30 + -6w + 9w = 6 + -9w + 9w
Combine like terms: -6w + 9w = 3w
30 + 3w = 6 + -9w + 9w
Combine like terms: -9w + 9w = 0
30 + 3w = 6 + 0
30 + 3w = 6
Add '-30' to each side of the equation.
30 + -30 + 3w = 6 + -30
Combine like terms: 30 + -30 = 0
0 + 3w = 6 + -30
3w = 6 + -30
Combine like terms: 6 + -30 = -24
3w = -24
Divide each side by '3'.
w = -8
Simplifying
w = -8</span>
Answer:
Step-by-step explanation: