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olga nikolaevna [1]
4 years ago
9

Graph the ellipse with equation x squared divided by nine plus y squared divided by sixteen = 1

Mathematics
2 answers:
Yakvenalex [24]4 years ago
8 0

Here is the picture of the answer above

gladu [14]4 years ago
6 0
X²/9 + y²/16 = 1

The general for mula of an ellipse is:

(x-h)²/a²  + (y-k)²/b² = 1. Since h = k = 0, this ellipse
x²/9 + y²/16 = 1
passes by the center O. (Note that a = 3 and b = 4)

Moreover sin b>a  so the majore axis is (on the y-axis) and a the minor axis (on the x-axis) [Its shape is as a vertical egg].

On a system of perpendicular axis that intercept in O., take on the x-axis 2 points A & B with respective coordinate A(3.0) and B(-3,0)
On the y-axis your report A'(0,+4) and B'(0,-4). So you have the vertex of the ellipse, then it's easy to draw it

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natta225 [31]

Answer:

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Step-by-step explanation:

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First thing you do is the parenthesis

6+4(5)^2

then the exponent

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then multiply

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106

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4 years ago
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photoshop1234 [79]

Answer:

u= 144

Step-by-step explanation:

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3 years ago
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
Suppose an initial investment of $100 will return $50/year for 3 years (assume the $50 is received each year at the end of the y
nydimaria [60]

With a positive NPV, it shows that the investment is profitable.

It is a profitable investment with a positive NPV at a discount rate of 20%.

Data and Calculations

Initial investment = $100

Annual cash inflows = $50

Period of investment = 3 years

Discount rate = 20%

<h3>What is the present value?</h3>

Present value (PV) is the current value of a future sum of money or stream of cash flows given a specified rate of return.

Present Value (PV) annuity factor for 3 years at 20% = 2.106

Present value of annual cash inflows = $105.3 ($50 x 2.106)

Net Present Value (NPV) = $5.3 ($105.3 - $100)

Thus, with a positive NPV, it shows that the investment is profitable.

To learn more about the investment visit:

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4 0
2 years ago
In this experiment researchers randomly assigned smokers to treatments. Of the 193 smokers taking a placebo, 29 stopped smoking
mezya [45]

Answer:

The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.

Step-by-step explanation:

To solve this question, we need to understand the Central Limit Theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard error is the square root of the sum of the variances:

Of the 193 smokers taking a placebo, 29 stopped smoking by the 8th day.

This means that:

p_S = \frac{29}{193} = 0.1503

s_S = \sqrt{\frac{0.1503*0.8497}{193}} = 0.0257

Of the 266 smokers taking only the antidepressant buproprion, 82 stopped smoking by the 8th day.

This means that:

p_A = \frac{82}{266} = 0.3083

s_A = \sqrt{\frac{0.3083*0.6917}{266}} = 0.0283

Calculate the estimated standard error for the sampling distribution of differences in sample proportions.

s = \sqrt{s_S^2 + s_A^2} = \sqrt{0.0257^2 + 0.0283^2} = 0.0382

The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.

7 0
3 years ago
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