the correct question is
The midpoint of kl is m(–8, 1). one endpoint is k(–6, 5). find the coordinates of the other endpoint l.
we know that
the formula of midpoint is
Xm=(x1+x2)/2----> 2*Xm=x1+x2------> x2=2*Xm-x1
Ym=(y1+y2)/2----> 2*Ym=y1+y2------> y2=2*Ym-y1
let
(x1,y1)-------> (–6, 5).
(Xm,Ym)-----> (-8,1)
find (x2,y2)
x2=2*Xm-x1-----> 2*(-8)-(-6)----> -10
y2=2*Ym-y1----> 2*(1)-5-----> -3
the point l is (-10,-3)
The radius would be 9 using the formula C=2r
The given figure can be divided in two parts 1) Square with side 7 in 2) A right triangle with base 12 in and height 7 in.
1) Area of square = 
Side of the square is 7 in.
Area = 
2) Area of triangle = 
Area of triangle =
Area of polygon= Area of square+ Area of triangle
Area of polygon = 49+42 =91 square in.
Area = 
Answer:
2.33 = BC
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan B = AC / BC
tan 25 = AC / 5
Multiply each side by 5
5 tan 25 = BC
2.331538291 = BC
To the nearest hundredth
2.33 = BC
