X=5
i can send the work if you need it
Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
Answer with Step-by-step explanation:
Since we have given that
a + b = c
and a|c
i.e. a divides c.
We need to prove that a|b.
⇒ a = mb for some integer m
Since a|c,
So, mathematically, it is expressed as
c= ka
Now, we put the above value in a + b = c.
So, it becomes,
a=mb, here, m = k-1
Hence, proved.
Answer:
hello!!!!
the answer is 280
im not really sure... read the description.... since i dont see a picture attached i dont know the figure shape which makes it difficult to guarantee the correct answer for you....
please read the explanation.. it always helps...
Step-by-step explanation:
okay im going to guess that the figure is a rectangular prism... if not please correct me
if so.... then...
2(10*5 + 10*6 + 5*6)= 280
Answer:
no
Step-by-step explanation:
yes
