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elixir [45]
3 years ago
15

Decide whether the statement is an example of the​ commutative,​ associative, identity,​ inverse, or distributive property.

Mathematics
2 answers:
erastovalidia [21]3 years ago
6 0

Associative Property of Addition is your answer.

This means that no matter which set of numbers is parenthesis (the one being done first), the answer is still going to be the same

hope this helps

nikdorinn [45]3 years ago
3 0

Associative Property of Addition is your answer.

This means that no matter which set of numbers is parenthesis (the one being done first), the answer is still going to be the same

hope this helps

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What is the 4th term of the expanded binomial (2x – 3y)^6
san4es73 [151]

Answer:

The 4th term of the expanded binomial is -4320x^3y^3

Step-by-step explanation:

Considering:

$ (x+y)^n = \sum_{k=0}^{n} \binom{n}{k}  x^{n-k}y^k$

$ (2x-3y)^6 = \sum_{k=0}^{6} \binom{6}{k}  (2x)^{6-k}(-3y)^k$

Now, you gotta calculate for every value of k

$ (2x-3y)^6 = \binom{6}{0}  (2x)^{6-0}(-3y)^0     +       \binom{6}{1}  (2x)^{6-1}(-3y)^1     +      \binom{6}{2}  (2x)^{6-2}(-3y)^2   +   \\ $

$\binom{6}{3}  (2x)^{6-3}(-3y)^3    +    \binom{6}{4}  (2x)^{6-4}(-3y)^4    +  \binom{6}{5}  (2x)^{6-5}(-3y)^5    +    \binom{6}{6}  (2x)^{6-6}(-3y)^6            $

I will not write every product, but just solve following the steps:

For k=0

$\binom{6}{0}  (2x)^{6-0}(-3y)^0$

$\frac{6!}{(6-0)!(0!)}   (2x)^{6-0}(-3y)^0$

$ \frac{6!}{6!} \left(2x\right)^{6-0}\cdot 1$

$1\cdot \:1\cdot \left(2x\right)^{6-0}$

$2^6x^6$

64x^6

(2x-3y)^6=64x^6-576x^5y+2160x^4y^2-4320x^3y^3+4860x^2y^4-2916xy^5+729y^6

8 0
3 years ago
What is the equation of the following direct variation?
Whitepunk [10]
The answer is D, becuSe the slope is -2/1
8 0
3 years ago
Read 2 more answers
(6) Simplify<br> (m 2)-3
zlopas [31]

Answer:

2m-3

Step-by-step explanation:

please verify your Q since it's not clear what is the equation..

7 0
3 years ago
If f(x)=x^2+2x+3, find f(1)
mash [69]

To solve this problem, we must substitute in 1 for the variable x in the equation. This is because the function as written is f(x), meaning that the function is evaluated as x currently, but we want to evaluate it at 1. To do this, all we have to do is replace each variable x with a 1 and simplify.

f(x) = x^2 + 2x + 3

f(1) = (1)^2 + 2(1) + 3

To simplify, we first to compute the exponents. This is because of the order of operations, which says that we should solve parentheses first, exponents next, then multiplication/division, then addition/subtraction last.

f(1) = 1 + 2(1) + 3

Next, as outlined above, we should perform the multiplication.

f(1) = 1 + 2 + 3

Finally, we can finish solving by adding together the remaining terms.

f(1) = 6

Therefore, your answer is 6.

Hope this helps!

5 0
3 years ago
Read 2 more answers
How can we express 499 in math?
erastovalidia [21]
ANSWER:

400 + 90 + 9 = 499
3 0
3 years ago
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