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2 years ago

If f(x)=x^2+2x+3, find f(1)

2 answers:

5 0

To solve this problem, we must substitute in 1 for the variable x in the equation. This is because the function as written is f(x), meaning that the function is evaluated as x currently, but we want to evaluate it at 1. To do this, all we have to do is replace each variable x with a 1 and simplify.

f(x) = x^2 + 2x + 3

f(1) = (1)^2 + 2(1) + 3

To simplify, we first to compute the exponents. This is because of the order of operations, which says that we should solve parentheses first, exponents next, then multiplication/division, then addition/subtraction last.

f(1) = 1 + 2(1) + 3

Next, as outlined above, we should perform the multiplication.

f(1) = 1 + 2 + 3

Finally, we can finish solving by adding together the remaining terms.

f(1) = 6

Therefore, your answer is 6.

Hope this helps!

Dafna11 [192]2 years ago

4 0

answer is 6...................

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3 years ago

In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal

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Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for 95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

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2 years ago

Read 2 more answers

The average cost per person of attending an online class depends on the number of people attending. If 20 people attend, the web

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Answer:

The last table given See attached image)

Step-by-step explanation:

Notice that they are asking for the inverse function to the one with the detailed relationship given. The original relationship was assigning to the Domain of number of people attending, the Range of values for charges.

Therefore, the inverse function will be assigning in the opposite way: from the average charges (now the Domain of this relationship), to the number of people attending (now the Range of this relationship). The relationship should also maintain the original element to element connection:

What was:

(20, $10) should now be ($10, 20)

(26, $6.25) should now be ($6.25, 26)

(35, $4) should now be ($4, 35)

This is exactly represented by the last table (see also image attached)